xy=(x+10)*(y-0.2) xy=(x-4)*(y+0.1)
[-(x-y)^2/xy]^-4*(y^2-xy/x)^3*(x^4/y^10)÷(xy-y^2/x)^-5=-y(y-
(-3x^y+2xy)-( )=4x^+xy
已知x-y=4xy,则2x+3xy-2yx-2xy-y
已知xy>0,证明xy+xy/1+x/y+y/x>=4
已知2x+xy=10,3y+2xy=6.求4x+8xy+9y=?
[(xy+2)(xy-2)-2x^2y^2+4]/xy,其中x=10,y=-1/25
[(xy+2)(xy-2)-2x^2y^2+4]/(xy),其中:x=10,y=-1/25
xy=-2,x+y=3,求代数式(4xy+12y)+[7x-(3xy+4y-x)]
已知X+Y=2XY,求4X-5XY+4Y 除以X+XY+Y 的值
已知x-y=4xy,求x-2xy-y分之2x+3xy-2y的值!
x y xy=10怎么算
xy+yx=10x,y是多少