化简1+sin(x-2π)*cos[x-(7π/2)]-tan(π-x)*tan(3π/2-x)-cos^2(-x)
来源:学生作业帮 编辑:搜搜考试网作业帮 分类:数学作业 时间:2024/06/16 21:36:18
化简1+sin(x-2π)*cos[x-(7π/2)]-tan(π-x)*tan(3π/2-x)-cos^2(-x)
1+sin(x-2π)*cos[x-(7π/2)]-tan(π-x)*tan(3π/2-x)-cos^2(-x) 怎么化啊
1+sin(x-2π)*cos[x-(7π/2)]-tan(π-x)*tan(3π/2-x)-cos^2(-x) 怎么化啊
1+sin(x)*cos(x+pi/2)+tan(x)*(-tan(x+pi/2))-(cos(x))^2
=1-(sin(x))^2-(cos(x))^2+ sin(x)/cos(x)*(-sin(x+pi/2)/cos(x+pi/2))
=1-((sin(x))^2+(cos(x))^2)+sin(x)/cos(x)*(-cos(x)/(-sin(x))
=1
=1-(sin(x))^2-(cos(x))^2+ sin(x)/cos(x)*(-sin(x+pi/2)/cos(x+pi/2))
=1-((sin(x))^2+(cos(x))^2)+sin(x)/cos(x)*(-cos(x)/(-sin(x))
=1
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