设f(x)=2x^2-2xf'(1),则f'(1)=
设f(x)=x^2+2xf'(1)则f'(-1)的值是?
设函数f(x)的导数为f‘(x),且f(x)=x²+2xf‘(1),则f‘(0)等于
设f''(x)在[0,1]上连续,f'(1)=0,且f(1)-f(2)=2,则∫(0,1)xf''(x)dx=
1)已知f(x)=x平方+3xf'(2),则f'(2)=?
已知f(x)=x^2+2xf'(1),则f
设F(x)是f(x)的一个原函数、证明积分xf(x^2)dx=1/2F(x^2)+C
设f(x)为连续函数,且满足f(x)=1+xf(t)dt/t^2从1到X的积分,试求f(x)
已知∫f(x)dx=xf(x)-∫x/√(1+x^2)dx,则f(x)=
设函数f(x)连续,则d∫xf(x^2)dx=?
设f(x)连续 则d∫(0,2x)xf(t)dt/dx=?
设f''(x)在[0,1]连续,且f(0)=1,f(2)=3,f'(2)=5,求∫[0,1]xf''(2x)dx
设f(x)在[a,b]上连续,f(a)=f(b)=0,定积分f^2(x)从b到a等于1,则定积分xf(x)f'(x)=-