lim(1-1/2^n)=1 n趋向于无穷大
极限计算 lim (1+2+3+...+n)/n^2=?(n趋向于无穷大)
证明lim(n/(n^2+1))=0(n趋向于无穷大)
证明 lim(1-1/2^n)=1 n趋向于无穷大
n趋向于无穷大,lim n[ln(n+2)-ln(n+1)],
用ε-Ν定义证明lim(1-n)/(1+n)=-1,n趋向于无穷大
高数极限证明 lim(1-n)/(1+n)=-1,n趋向于无穷大
lim n趋向于无穷大,n[(根号下n平方+1)-(根号下n平方-1)]
求极限 lim n[1/(n^2+1)+1/(n^2+2^2)+……+1/(n^n+n^n)] (n趋向于无穷大,n^n
求下列极限.lim(n趋向于无穷大)(2x次方)*(sin*1/2x次方)
lim n趋向无穷大(3^n+2^n)/(3^(n+1)-2^(n+1))=?
lim(1+1/n+1)^n.趋向无穷大
紧急:求 lim n*sin(π(n^2+2)^0.5)*(-1)^n,n趋向无穷大;