求极限4x2+3x-5/x2-7x-12
求lim x2+2x+5/3x2-x+1怎么用那个公式求极限?
1/(x2+3x+2)+1/(x2+5x+6)+1/(x2+7x+12)=1/(x+4)
解方程:1/x2+x +1/x2+3x+2 +1/x2+5x+6 +1/x2+7x+12 +1/x2+9x+20=5/x
求多项式3x2-6x+5与4x2+7x-6的和.
求极限(1/x2)ln(arctanx/x),
1/(x2+x)+1/(x2+3x+2)+1/(x2+5x+6)+1/(x2+7x+12)=4/21
计算极限 lim X2-3X+2 -------------- x→2 X2+5X-6
5x2—[x2+(4x—x2)—2(x2—3x)]
(x2+3x+12)(x2+7x+12)-120
3x2-[7x-(4x-3)-2x2]
求极限lim X→∞ [1+ x2/2 -√(1+ x2)]/(cos x –e x2 )sin x2 亲
1/x2-3x+2+1/x2-5x+6+1/x2-7+1/x2-7x+12-4/x2-6x+5 有多少种写多少种解法,