10X+Y+1/3Z=10Y+X 10X+Y+2/3Z=100X+Y

若{x+3y+10z=0 则 (x+y-z)/(x-y+z) (4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai 三元一次方程组数学题x+2y+2z=33x+y-2z=72x+3y-2z=10x-y=2z-x=3y+z=-1x-y-z 3x+2y+z=14 ,x+y+z=10,z+2x+3y=1 5 [3x+2y+z=14,x+y+z=10,2x+3y-z=1] (x-2y+z)/9=(2x+y+3z)/10=-(3x+2y-4z)/3=1 连等,求x,y,z, 试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) x+2y+3z=10,x-y+4z=10,x+3y+2z=2 x-y+4z=10,x+3y+2z=2,x+2y+3z=11. x+y+z=4 2x+3y-z=6 3x+2y+2z=10 {2x+3y-4z=-5 x+y+z=6 x-y+3z=10 2X+Y+Z=10,X+2Y+Z=-6,X+Y+2Z=8 5X+4Y-3Y=13,2X-3Y+7Z=19,3X-Y=2X