lim(3^2n+5^n)/(1+9^n)=?
lim(3^2n+5^n)/(1+9^n)
lim 9^n+4^n+2/5^n-3^2n-1 n趋于无穷大时
lim[(n+3)/(n+1))]^(n-2) 【n无穷大】
lim(n->∞){1/2*4+1/3*5+...+1/(n+1)(n+3)=?
极限计算:lim { [1+3+5+…+(2n+1)] / (n^2) }^(n)=(
lim(n->无穷)[(3n^2+cn+1)/(an^2+bn)-4n]=5
求极限 lim(n→∞)[根号(n^2+4n+5)-(n-1)] =
lim n->无穷大(2^n-1)/(3^n+1)
lim根号n^2+n+1/3n-2
求lim n→∞ (1+2/n)^n+3
lim n属于无穷大 (n+1)(n+2)(n+3)/5n的三次方 要求极限...我看到答案上是 化成 1/5lim n
lim n趋向无穷大(3^n+2^n)/(3^(n+1)-2^(n+1))=?