设数列{an}的前n项和为Sn,a1=1,3S2n=an(3Sn-1)(n∈N*,n≥2) (1)证明:数列{1/Sn}
已知数列{an}的前n项和为Sn,a1=-23,Sn+1Sn=an-2(n≥2,n∈N)
已知数列{an}的首项是a1=1,前n项和为Sn,且Sn+1=2Sn+3n+1(n∈N*).
已知数列an的首项a1=5,前n项和为Sn,且S(n+1)=2Sn+n+5(n∈N*),求数列{an}的前n项和Sn,设
设数列an的前n项和为Sn,a1=1,an=(Sn/n)+2(n-1)(n∈N*) 求证:数列an为等差数列,
设数列{an}的前n项和为Sn,若a1=1,an+1=3Sn(n∈N*),则S6=( )
设数列an的前n项和为Sn,a1=1 ,an = 2Sn²/2Sn-1 (n≥2)
数列{an}的前n项和为Sn,已知A1=a,An+1=Sn+3^n(三的n次方),n∈N*
已知数列{an}的首项a1=3,前n项和为Sn,且S(n+1)=3Sn+2n(n∈N)
设数列an的前n项和为sn,且a1为1 ,Sn+1=4an+2(n∈N正)
已知数列{an}的前n项和为Sn,Sn=(an-1)/3 (n∈N)
设Sn是数列an的前n项和,已知a1=1,an=-Sn*Sn-1,(n大于等于2),则Sn=
数列An的前n项和为Sn,已知A1=1,An+1=Sn*(n+2)/n,证明数列Sn/n是等比数列