化简求职:(2x-y+3z)(-2x-y-3z)-(x+2y-3z)²
来源:学生作业帮 编辑:搜搜考试网作业帮 分类:数学作业 时间:2024/06/23 03:26:27
化简求职:(2x-y+3z)(-2x-y-3z)-(x+2y-3z)²
化简求值:(2x-y+3z)(-2x-y-3z)-(x+2y-3z)²
化简求值:(2x-y+3z)(-2x-y-3z)-(x+2y-3z)²,其中x=1,y=-1,z=1
化简求值:(2x-y+3z)(-2x-y-3z)-(x+2y-3z)²
化简求值:(2x-y+3z)(-2x-y-3z)-(x+2y-3z)²,其中x=1,y=-1,z=1
(2x-y+3z)(-2x-y-3z)-(x+2y-3z)²
=-(2x-y+3z)(2x+y+3z)-(x+2y-3z)²
=-[(2x+3z)²-y²]-(x+2y)²+6z(x+2y)-9z²
=-4x²-12xz-9z²+y²-x²-4xy-4y²+6xz+12yz-9z²
=-5x²-3y²-18z²-6xz+12yz-4xy
再问: 化简求值:(2x-y+3z)(-2x-y-3z)-(x+2y-3z)²,其中x=1,y=-1,z=1
再答: (2x-y+3z)(-2x-y-3z)-(x+2y-3z)² =-(2x-y+3z)(2x+y+3z)-(x+2y-3z)² =-[(2x+3z)²-y²]-(x+2y)²+6z(x+2y)-9z² =-4x²-12xz-9z²+y²-x²-4xy-4y²+6xz+12yz-9z² =-5x²-3y²-18z²-6xz+12yz-4xy 当x=1,y=-1,z=1时 原式=-5-3-18-6-12+4 =-40
=-(2x-y+3z)(2x+y+3z)-(x+2y-3z)²
=-[(2x+3z)²-y²]-(x+2y)²+6z(x+2y)-9z²
=-4x²-12xz-9z²+y²-x²-4xy-4y²+6xz+12yz-9z²
=-5x²-3y²-18z²-6xz+12yz-4xy
再问: 化简求值:(2x-y+3z)(-2x-y-3z)-(x+2y-3z)²,其中x=1,y=-1,z=1
再答: (2x-y+3z)(-2x-y-3z)-(x+2y-3z)² =-(2x-y+3z)(2x+y+3z)-(x+2y-3z)² =-[(2x+3z)²-y²]-(x+2y)²+6z(x+2y)-9z² =-4x²-12xz-9z²+y²-x²-4xy-4y²+6xz+12yz-9z² =-5x²-3y²-18z²-6xz+12yz-4xy 当x=1,y=-1,z=1时 原式=-5-3-18-6-12+4 =-40
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
x/2=y/3=z/5 x+3y-z/x-3y+z
1.(x+y-z)+(x-y+z)-(x-y-z) 2.2x-(3x-2y+3)-(5y-2)
因式分解:25x y^2 z^2 (x+y-z)-30xyz(z-x-y)^2+5x y z^3 (z-x-y)
已知x,y,z 大于0,x+y+z=2,求证 xz/y(y+z)+zy/x(x+y)+yx/z(z+x)大于等于2/3
x=y/z=z/3,x+y+z =12,求2x+3y+4z是多少,
证明:(y+z-2x)3+(z+x-2y)3+(x+y-2z)3=3(y+z-2x)(z+x-2y)(x+y-2z).
如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0求x,y,
(2x-3y+z)-3{x-2【-z+(x-y)】-(3y-5z)}
(y-x)/(x+z-2y)(x+y-2z)+(z-y)(x-y)/(x+y-2z)(y+z-2x)+(x-z)(y-z
(x-3y+2z)²=
已知2x+3y-4z=0,3x+4y+5z=0,求x+y+z/(除以)x-y+z的值.