x^2+y^2+z^2-2x+4y-6y+14=0,求x+y+z 求助,谢谢
已知x²+y²+z²-2x+4y-6z+14=0,求x+y-z/x+y+z的值
已知x、y、z满足方程组:x+y-z=6;y+z-x=2;z+x-y=0 求x、y、z的值
如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0求x,y,
已知有理数x、y、z满足条件|x-z-2|+(3x-6y-7)^2+|3y+3z-4|=0,求x、y、z
已知4x-3y-6y=0,x+2y-7z=0.求x-y+z\x+y+z的值
已知x,y,z满足方程组{x+y-z=6{y+z-x=2{z+x_y=0,求x,y,z的值
若4x-3y-6z=0,x+2y-7z=0,求代数式5x*5x+2y*2y-z*z/2x*2x-3y*3y-10z*10
已知3x-2y-5z=0,2x-5y+4z=0,且x,y,z均不为0,求3x*x+2y*y+5z*z/5x*x+y*y-
已知x,y,z满足方程组{x+y-z=6,y+z-x=2,z+x-y=0,求x,
1.已知x,y,z满足2│x-y│+(根号2y-z)+z平方-z+(1/4)=0,求x,y,z值.
x^2+y^2+z^2+4x+4y+4z+1=0,求x+y+z
x^2+y^2+z^2+4x+4y+4z+1=0求x+y+z