如果{an}成等差数列,求证:a1Cn0+a2Cn1+a3Cn2+……+a(n+1)Cnn=[a1+a(n+1)]2^(
来源:学生作业帮 编辑:搜搜考试网作业帮 分类:数学作业 时间:2024/06/25 08:01:02
如果{an}成等差数列,求证:a1Cn0+a2Cn1+a3Cn2+……+a(n+1)Cnn=[a1+a(n+1)]2^(n-1)
![如果{an}成等差数列,求证:a1Cn0+a2Cn1+a3Cn2+……+a(n+1)Cnn=[a1+a(n+1)]2^(](/uploads/image/z/17577324-36-4.jpg?t=%E5%A6%82%E6%9E%9C%7Ban%7D%E6%88%90%E7%AD%89%E5%B7%AE%E6%95%B0%E5%88%97%2C%E6%B1%82%E8%AF%81%EF%BC%9Aa1Cn0%2Ba2Cn1%2Ba3Cn2%2B%E2%80%A6%E2%80%A6%2Ba%28n%2B1%29Cnn%3D%5Ba1%2Ba%28n%2B1%29%5D2%5E%28)
等式左边的求和跟等差数列的求和是一个原理.
![](http://img.wesiedu.com/upload/3/db/3db7ce91f766d788e1323ac3e3f9d1c3.jpg)
![](http://img.wesiedu.com/upload/3/db/3db7ce91f766d788e1323ac3e3f9d1c3.jpg)
在数列{an}中,a1=2,a(n+1)=an+2^n+1?(1)求证:数列{an-2^n}为等差数列;?(2)设...
已知数列{an}满足a1=3 an*a(n-1)=2a(n-1)-1,求证数列{1/(an-1)}是等差数列,并求出数列
已知数列{an}中a1=-1且(n+1)an,(n+2)an+1(是下标)成等差数列,设bn=(n+1)an-n+2求证
已知数列{an}满足a1+a/4,(1-an)a(n+1)=1/4,令bn+an-1/2 求证数列{1/bn}为等差数列
已知数列{an}满足a1=2,a(n+1)=(3an-2)/(2an-1),求证{1/(an-1)}是等差数列,并求数列
已知{an}满足a1=2,a(n+1)=(2an)/(an+2),求证{1/an}为等差数列.
在数列a(n)中,a1=1.a(n+1)=a(n)+2分之2a(n)求证 an分之1为等差数列,并求an的通向公式:2,
设数列 an 的前n项和为Sn,a1=1,an=Sn/n+2(n-1)(n∈N*) 求证:数列{an}为等差数列,并求a
求证Cn0Cn1+Cn1Cn2+……+Cn(n-1)Cnn=(2n)!/(n-1)!(n+1)!
已知等差数列{an}满足a(n+1)=an+3n+2,且a1=2,求an.
已知数列{an}是等差数列,且bn=an+a(n-1),求证bn也是等差数列
设数列an的前n项和为Sn,a1=1,an=(Sn/n)+2(n-1)(n∈N*) 求证:数列an为等差数列,