解dy/dx+1/3y=1/3*(1-2x)y^4
从(dx)/(dy)=1/y '导出:(d^2x)/(dy^2)=-y''/(y')^3
试从dx/dy=1/y'导出:d^2x/dy^2=-y''/(y')^3 题目中关于d[1/y']/dx}*[dx/dy
dy/dx-2y/(1+x)=(x+1)^3
x^2+xy+y^3=1,求dy/dx
dy/dx 3x^2+4y^3-2x-5y+1=0
y=f(x)由x^2+3y^4+x+2y=1所确定,求dy/dx
已知dx/dy=1/y',求证1、d^2x/dy^2=-y''/(y')^3.2、d^3x/dy^3=[3(y'')^2
高数中高阶导数,dx\dy=1\y',d^2x\dy^2=-y''\3(y')^2
设函数y=3^1/X,dy/dx=()
y=Insin(3x-1),求dx分之dy
y=(3x+1)^5 求dy/dx
解, Dy/Dx + y = x , y(0) = 1