（1+y）^2-2x^2(1+y^2)+x^4(1-y)^2

来源：学生作业帮编辑：搜搜考试网作业帮分类：数学作业时间：2024/06/05 03:27:51

(1+y)^2-2x^2(1+y^2)+x^4(1-y)^2
=(1+y)^2-2x^2(1+y)(1-y)+x^4(1-y)^2-4x^2y^2
=[(1+y)-x^2(1-y)]^2-4x^2y^2
=(1+y-x^2+x^2y)^2-(2xy)^2
=(1+y+2xy-x^2+x^2y)(1+y-2xy-x^2+x^2y)
=[(1-x^2)+(yx+y)+(x^2y+xy)][(1-x^2)-(xy-y)+(x^2y-xy)]
=(x+1)(x-1)(x-xy+1+y)(x-xy-1-y)

1、x(x-y)(x+y)-x(x+y)^2 [(-x-y)(-x+y)-(x+y)^2-x(y-y^2)}÷1/2y (1)(x^2/x)-y-x-y 1) (2x+5y)(2x-5y)(-4x^2-25y^2) 2) [（x+y)(x-y)-(x-y)^2+2y(x-y 1 4(x-y+1)+y(y-2x) 把4（x-y+1)+y(y-2x)因式分解 4(x-y+1)+y(y-2x) 若|x+2y-1|+y²+4y+4=0,求（2x-y）²-2（2x-y)(x+2y)+(x+2y)& （x+2)(x+3) (x-4)(x+1) (y+4)(y-2) (y-5)(y-3) 已知4x=9y求(1)x+y/y (2)y-x/2x {3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1 (1)(x+y)^2-(x-y)^2