已知数列{an}为等差数列,前n项为Sn,且Sn=25,S2n=100,那么S3n等于
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已知数列{an}为等差数列,前n项为Sn,且Sn=25,S2n=100,那么S3n等于
![已知数列{an}为等差数列,前n项为Sn,且Sn=25,S2n=100,那么S3n等于](/uploads/image/z/16245416-56-6.jpg?t=%E5%B7%B2%E7%9F%A5%E6%95%B0%E5%88%97%7Ban%7D%E4%B8%BA%E7%AD%89%E5%B7%AE%E6%95%B0%E5%88%97%2C%E5%89%8Dn%E9%A1%B9%E4%B8%BASn%2C%E4%B8%94Sn%3D25%2CS2n%3D100%2C%E9%82%A3%E4%B9%88S3n%E7%AD%89%E4%BA%8E)
Sn=a1+a2+...+an=25
S2n=a1+a2+...+an+a(n+1)+a(n+2)+...+a(n+n)=a1+a2+...+an+a1+nd+a2+nd+...+an+nd
=2(a1+a2+...+an)+n²d=2×25+n²d=100
n²d=50 a(n+1)+a(n+2)+...+a(2n)=100-25=75
S3n=a1+a2+...+an+a(n+1)+a(n+2)+...+a(n+n)+a(n+n+1)+a(n+n+2)+...+a(n+n+n)
=a1+a2+...+an+2[a(n+1)+a(n+2)+...+a(n+n)]+n²d
=25+2×75+50
=225
S2n=a1+a2+...+an+a(n+1)+a(n+2)+...+a(n+n)=a1+a2+...+an+a1+nd+a2+nd+...+an+nd
=2(a1+a2+...+an)+n²d=2×25+n²d=100
n²d=50 a(n+1)+a(n+2)+...+a(2n)=100-25=75
S3n=a1+a2+...+an+a(n+1)+a(n+2)+...+a(n+n)+a(n+n+1)+a(n+n+2)+...+a(n+n+n)
=a1+a2+...+an+2[a(n+1)+a(n+2)+...+a(n+n)]+n²d
=25+2×75+50
=225
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