sin(π/3+x)=1/3,则sin(π/6+2x)= 我看了几个例题,他们把sin换成了cos 这个是怎么转换的?

怎么把sin(x-π/2)换成以cos表示? 函数f(x)=cos2x+cos(x+π/3)+sin(x+π/6)+3sin^2x的最小值 三角等式求证：cos^6x+sin^6x=1-3sin^2x+3sin^4x 化简：1、sin(x-π/3)-cos(x+π/6)+√3cosx=?2、已知,sinα+sinβ=√2/2,求cosα 函数f(x)=(sin x-1)/(3-2cos x-2sin x)^(1/2) (0≤x≤2π) 的值域是( ) f(x)=2cos*sin(x+π/3)-^3sin^2x+sinx*cosx 若sin x/2-cos x/2=1/3,则sin x= 若sin x/2 - cos x/2 = 1/3,则sin x=? 已知(1+sin x)/cos x=1/2,则cos x/(sin x-1)的值是 sin^2x+cos^2y=1/2 求3sin^2x+sin^2y的最值 已知函数f(x)=2cos(x-π/6)sin(x+π/6)-√3*(sin(x-π/6))^2+sin(x-π/6)c 已知函数f(x)=cos(2x-π/3）+2sin(x-π/4）sin(x+π/4)=sin(2x-π/6) ,