搜搜考试网z为复数.建立恒等式1+z+z^2+z^3+···+z^n=[1-z^(n+1)]/（1-z）(z不等于1）并导出：1+
![z为复数.建立恒等式1+z+z^2+z^3+···+z^n=[1-z^(n+1)]/（1-z）(z不等于1）并导出：1+](/uploads/image/z/15942419-35-9.jpg?t=z%E4%B8%BA%E5%A4%8D%E6%95%B0.%E5%BB%BA%E7%AB%8B%E6%81%92%E7%AD%89%E5%BC%8F1%2Bz%2Bz%5E2%2Bz%5E3%2B%C2%B7%C2%B7%C2%B7%2Bz%5En%3D%5B1-z%5E%28n%2B1%29%5D%2F%EF%BC%881-z%EF%BC%89%28z%E4%B8%8D%E7%AD%89%E4%BA%8E1%EF%BC%89%E5%B9%B6%E5%AF%BC%E5%87%BA%EF%BC%9A1%2B)
若复数z满足z^n=1,其中n属于N+,则1+z+z^2+...+z^n=
已知复数Z满足|Z-4|=|Z-4i|.且Z+(14-z)/z-1为实数,求z.
已知复数z满足z·z的共轭+(1-2i)z+(1+2i)z的共轭=3,求|z|的最值
已知复数z满足3z+(z-2)i=2z-(1+z)i,求z
复数Z满足1/Z=Z/(3Z-10)则,|Z|=
已知复数z满足z*z-3i*z=1+3i,求z
已知复数z满足z+1/z∈R,|z-2|=2,求z
复数z满足|3z+1|=|z-
复数z满足(z-1)(2-z)=5
复数Z,绝对值z=1,绝对值（z^2-z+1）=1,则z=?
求满足｜（z+1）/(z-1)｜=1,且z+2/z∈R的复数z.
若复数Z满足|Z|=1,则|Z^2-Z|的最大值为?