利用1/n*(n+1) = 1/n - 1/(n+1)计算1/(x-2)(x-3)-2/(x-1)(x-3)+1/(x-
计算(x^(2n)+x^n+1)(x^(3n)-x^(2n)+1)
C语言 f(x)=1+x+x^2/2!+x^3/3!+...+x^n/n!直到|x^n/n|
计算:(x^3)^n÷x^2n÷x^n-1
计算x^3n/(x^2-1)-x^2n/(x^n+1)-1/(x^n-1)+1/(x^n+1)
计算:1/(x-1)+1/(x-1)(x-2)+1/(x-2)(x-3)+.+1/(x-n)(x-n-1)
C语言:用迭代法求平方根.利用公式x(n+1)=1/2*(x(n)+a/x(n)) 计算a的平方根.要求|x(n+1)-
计算(-x)^2n十1.(-x)^n+1
\求和Sn=1+2x+3x^2+```+(n-1)x^(n-2)+n*x^(n-1)
求和:Sn=1-3x+5x^2-7x^3+.+(2n+1)(-x)^n(n属于N*)
计算:(m+2n)/(n-m)+n/(m-n)-2m(n-m)和[(x+2)/(x×x-2x)-(x-1)/(x×x-4
x^2n(x^2-2n-2x^1-2n+x^-2n)
因式分解4x^(n+2)-9x^n+6x^(n-1)-x^(n-2)