int x=0,s=0;while(!=0) s+=++x printf("%d",s);
设有一下程序 int x=0 ,s=0; while(!=0)s+=++x; printf(''%d'',s);求结果
int x=20;printf(“%d”,0
int i=1,s=0;do { s+=i;i++};while(i<=5); printf("%d\n
#define S(x)4 *(x)*x+1 main() {int k=5,j=2;printf("%d\n",S(k
void main() { int x=0,y=5,z=3; while() printf("%d,%d,%d\n",x
#define FOR while(x--) int x=3,y=0; FOR {y++; } printf("x=%d
5.main() { int x; x=3; do { printf(“%d”,x--); }while(!x);
main( ) {int x=3; do {printf("%d\n",x-=2;} while (--x)); }
int x = 3; do { printf("%3d",x -= 2 ); } while ( ( --x) ); (
#includemain(){int x=3;do{printf("%3d\n",x-=2);}while(!(--x)
#includemain(){int x=3;do{printf("%d\n",x-=2);}while(!(--x))
int x=23;do {printf ("%d",x--);}while(!x);有没有详细一点的解释?