如图,在△ABC、△AED中,AB=AC,AD=AE,且∠CAB=∠DAE.
如图,在△ABC、△AED中,AB=AC,AD=AE,且∠CAB=∠DAE.⑴问CE与BD有什么关系?为什么?⑵若将△A
17.如图1,在直角△ABC和△AED中,AC=AB,AD=AE,∠BAC90°,∠DAE=90°,连接CD,点G是CD
如图,在正△ABC中,D,E分别在AC,AB上,且AD/AC=1/3,AE=BE.求证:△AED~△CBD.
如图(1),△ABC和△ADE中,已知AB=AC,AD=AE,且∠CAB=∠EAD
如图,在△ABC和△ADE中,AB=AC,AD=AE,∠BAC=∠DAE,求证:△ABD≌△ACE.
如图,在△ABC和△ADE中,AB=AC,AD=AE,∠BAC=∠DAE=90°.①求证:C
如图,在△ABC和△ADE中,AB=AC,AD=AE,∠BAC=∠DAE=90°.
如图,在△ABC中,AD平分∠BAC.在AB上截取AE=AC,连结DE.说明△AED ≌△ACD的理由
如图,在△ABE中,AB=AE,AD=AC,∠BAD=∠EAC,BC、DE交于点O.∠ABC=∠AED;
如图,在△ABC中,E是AC上一点,且AE=BC,AD‖BC,∠AED=∠CBE.
已知:如图①所示,在△ABC和△ADE中,AB=AC,AD=AE,∠BAC=∠DAE=α,且点B,A,D在一条直线上,连
如图,在△ABC和△ADE中,AB=AC,AD=AE,且∠BAC=90°,∠DAE=90°,点BCD在同一条直线上