ab/(a+b-1)(a+b)+ab/(a+b)(a+b+1)+ab/(a+b+1)(a+b+2)+…+ab/(a+b+
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ab/(a+b-1)(a+b)+ab/(a+b)(a+b+1)+ab/(a+b+1)(a+b+2)+…+ab/(a+b+98)(a+b+99)+ab/(a+b+99)(a+b+100)的值
a=1 b=-3
a=1 b=-3
原式=ab[1/(a+b-1)(a+b)+1/(a+b)(a+b+1)+1/(a+b+1)(a+b+2)+…+1/(a+b+98)(a+b+99)+1/(a+b+99)(a+b+100)]=ab[1/(a+b-1)-1/(a+b)+1/(a+b)-1/(a+b+1)+1/(a+b+1)-1/(a+b+2)+…+1/(a+b+98)-1/(a+b+99)+1/(a+b+99)-1/(a+b+100)]
=ab[1/(a+b)-1/(a+b+100)]=75/49
=ab[1/(a+b)-1/(a+b+100)]=75/49
ab+a+b+1
计算ab/(a+b-1)(a+b)+ab/(a+b)(a+b+1)+ab/(a+b+1)(a+b+2)+.+ab/(a+
急……ab/(a+b-1)(a+b) + ab/(a+b)(a+b+1) + ab(a+b+1)(a+b+2) + ……
a+b/2ab
2AB/A+B
a(a-1)-(a×a-b)=-5,求(a×a+b×b)÷2-ab
1+a+ab+b=?
ab(a-b)-a(b-a)
(a-b)(a^2+ab+b) 化简
求证:A/(AB+B^2)-B/(AB+A^2)=1/B-1/A
如果a+b=3,ab=-1,那么(a+b)2-a-b+ab=?
a^+2ab+b^-2a-2b+1 因式分解