已知/b-2/=(ab-2)^2=0,求1/(a+2007)(b+2007)+1/(a+2006)(b+2006).+1
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已知/b-2/=(ab-2)^2=0,求1/(a+2007)(b+2007)+1/(a+2006)(b+2006).+1/(a+2)(b+2)+1/(a+1)(b+1)的值
应该是
|b-2|+(ab-2)^2=0
吧
|b-2|+(ab-2)^2=0
b-2=0
ab-2=0
a=1
b=2
1/(a+2007)(b+2007)+1/(a+2006)(b+2006).+1/(a+2)(b+2)+1/(a+1)(b+1)
=1/(1+2007)(2+2007)+1/(1+2006)(2+2006)+.+1/(1+2)(2+2)+1/(1+1)(2+1)
=1/2008*2009+1/2007*2008+.+1/3*4+1/2*3
=(1/2008-1/2009)+(1/2007-1/2008)+.+(1/3-1/4)+(1/2-1/3)
=-1/2009+1/2
=2007/4018
|b-2|+(ab-2)^2=0
吧
|b-2|+(ab-2)^2=0
b-2=0
ab-2=0
a=1
b=2
1/(a+2007)(b+2007)+1/(a+2006)(b+2006).+1/(a+2)(b+2)+1/(a+1)(b+1)
=1/(1+2007)(2+2007)+1/(1+2006)(2+2006)+.+1/(1+2)(2+2)+1/(1+1)(2+1)
=1/2008*2009+1/2007*2008+.+1/3*4+1/2*3
=(1/2008-1/2009)+(1/2007-1/2008)+.+(1/3-1/4)+(1/2-1/3)
=-1/2009+1/2
=2007/4018
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