​5x−y=2(1) ​3y−x=8(2)

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​5x−y=2(1) ​3y−x=8(2)
化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1

原式=(9x²+24xy+16y²-4x²+y²-5x²+6xy-y²)÷(-2y)=(30xy+16y²)÷(-2y)=-15x

6(x-y)-2(x+y)=14 3(x-y)+(x+y)=5

设x-y=mx+y=n则6m-2n=143m+n=5解得m=2n=-1即x-y=2x+y=-1解得x=1/2y=-3/2

已知x,y满足约束条件x−y+5≥0x+y≥0x≤3,则z=x+2y的最小值为(  )

作出不等式组x−y+5≥0x+y≥0x≤3表示的平面区域,得到如图的△ABC及其内部,其中A(3,-3),B(3,8),C(-52,52)设z=F(x,y)=x+2y,将直线l:z=x+2y进行平移,

3(x+y)-4(x-y)=11,2(x-y)+5(x+y)=27

化简得:-x+7y=11①7x+3y=27②①式×7得:-7x+49y=77③②+③得:52y=104∴y=2代入①得:x=3∴x=3,y=2再问:亲,是代入法哦!再答:代入法①式得3x+3y-4x+

(x+2)(x+3) (x-4)(x+1) (y+4)(y-2) (y-5)(y-3)

(x+2)(x+3)=x²+5x+6(x-4)(x+1)=x²-3x-4(y+4)(y-2)=y²+2y-8(y-5)(y-3)=y²-8y+15x²

已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)

因为(x-y)/(x+y)=3,则(x+y)/(x-y)=1/3则5(x-y)(x+y)-(x+y)/2(x-y)=5*3-1/(3*2)=15-1/6=89/6

(2x+y-1)(2x-y+1)-(3x+y)(3x-y),其中x=5分之1,

(2x+(y-1))(2x-(y-1))=4x^2-(y-1)^2(3x+y)(3x-y)=9x^2-y^2相减得4x^2-y^2+2y-1-9x^2+y^2=-5x^2+2y-1带入得-5*1/25

3x-2y=1 4x-5y

条件不完全.补充后给你解答.4x-5y是4x=5y还是缺少了等号后的值?再问:4x-5y=3再答:

先化简再求值(x-y)(x+y)-(x-2y) 的完全平方+x(3x-5y)-(x-y)(x-2y),其中x=1/2 y

解(x-y)(x+y)-(x-2y)²+x(3x-5y)-(x-y)(x-2y)=(x²-y²)-(x²-4xy+4y²)+(3x²-5xy

解方程组{(x-2)(y+3)=(x+1)(y-1) {(x+1)(y+1)=(x-1)(y+5)

{(x-2)(y+3)=(x+1)(y-1){(x+1)(y+1)=(x-1)(y+5){xy+3x-2y-6=xy-x+y-1{xy+x+y+1=xy+5x-y-5{4x-3y=5(1){4x-2y

{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1

3(x+y)-4(x-y)=4(x+y)/2+(x-y)/6=1令a=x+y,b=x-y3a-4b=4(1)a/2+b/6=1则3a+b=6(2)(2)-(1)5b=2b=2/5a=(6-b)/3=2

3X+5y=2 x+y=1

再算再答:在再答: 

7x-3y/5=5x-y/3-x+y/2 x-1/5=y+1/3

先将第一条式子移项得到7x-5x+x=3y/5+y/2-y/3(右边通分)得到x=23y/90(1)第二式子两边同乘以15得到15x=15y+8(2)把(1)代入(2)中得到的结果自己算啊!

化简求值(x+2y)^2-(2x+y)(2x-y)-5y(y-x) 其中 x=1/3 y= -1/2

(x+2y)²-(2x+y)(2x-y)-5y(y-x)=x²+4xy+4y²-(4x²-y²)-(5y²-5xy)=x²+4xy

设z=2x+y,变量x,y满足条件x−4y≤−33x+5y≤25x≥1

满足x−4y≤−33x+5y≤25x≥1的平面区域如下图所示:由图可知,当直线z=2x+y经过点A(5,2)时,即当x=5,y=2时,2x+y取得最大值12,同理,当x=1,y=1时,2x+y取得最小

x+y=3 x+2y=9 3/x+1=y y-x=3 y=2x-3 y-3x=1 2(x+1)-y=6 7x-5y=-9

x+y=3则y=3-x带入x+2y=9解得x=-3,y=6剩下的都这样解

换元法解方程组3/x+y+2/x-y=17/5 2/x+y-5/x-y=1

设1/x+y=t1/x-y=v则3t+2v=17/52t-5v=16t+4v=34/56t-15v=319v=19/5v=1/5t=11/x+y=11/x-y=1/5x+y=1x-y=5x=3y=-2

已知x=1/3,y=-1/2,求代数式x-(x+y)+(x+2y)-(x+3y)+(x+4y)-(x+5y)+...-(

原式=x-x+x-x+……-x+(2-1+4-3+5-4+……+2008-2007-2009)y=0+(1×1004-2009)y=-1005y=1005/2