y=f^2(sin x)可导,求dy-搜答案-搜搜考试网

y=f(sinx),f(u)可微,则dy=d(f(sinx))=f'(sinx)cosx

y'=cosx/x^2－2sinx/x^3=(xcosx－2sinx)/x^3.

y'=f'(ln(x+√(a+x²)))·ln(x+√(a+x²))‘=f'(ln(x+√(a+x²)))·1/(x+√(a+x²))·(x+√(a+x

这是一个复合函数y=f(u(x))的求导,按下面公式：y'=f'(u)*u'(x)所以导数为：f'(x^2)*2x

y'=f'(e^(-2x)+cosx)(e^(-2x)'+cos'x)=f'(e^(-2x)+cosx)(-2e^(-2x)-sinx)

y'=1/(x-1)+f'(sinx)cosx

y'x=f'(sinx)*cosx-f'(cosx)sinx

y=f(sinx^2),求dy

复合函数的求导法则:如果u=g(x)在点x可导,而y=f(u)在点u=g(x)可导,则复合函数y=f[g(x)]在点x可导,且其导数为dy/dx=f'(u)g'(x)或dy/dx=(dy/du)(du

令u=x+arctanx,则u'=1+1/(1+x^2)则y=f^2(u)dy/dx=2f(u)f'(u)u'=2f(u)f'(u)[1+1/(x+x^2)]

设f（x）导数为f’（x）则y=f（(sinx)^2）+f（(cos)^2）的导数为f’（(sinx)^2）*2sinxcosx-f’（(cos)^2）*2cosxsinx=2sinxcosx[f’（

再问：��Ҫ��cosxô再答：��Ȼ�Ǹ��Ϻ��˳��

y'=cosx-3sin²xcosx

y=f[(e^x)sinx]z=(e^x)sinxz'=e^xsinx+e^xcosxy'=z'f'(z)=e^x(sinx+cosx)f'(z)

f(x)=x^2的导数为f′(x)=2x.如果f(x)=x^2为导函数,原函数F（x)=1/3×x³.最近有点分不清就全写上吧!

y=f[e^(1/sinx)]y'=f'[e^(1/sinx)]*[e^(1/sinx)'=f'[e^(1/sinx)]*e^(1/sinx)*(1/sinx)'=f'[e^(1/sinx)]*e^(

恩,dy＝df(sinx)＝f'(sinx)*d(sinx)＝f'(sinx)*cosxdx结果到这里应该可以了吧?

f(x)=ʃ(sinx)^2dx=1/2*ʃ(1-cos2x)dx=1/2x-1/4ʃcos2xd2x=1/2x-1/4sin2x+C很高兴为您解答,【中学生数理化】团队

两边对x求导xy^2+sinx=e^yy^2+2xyy'+cosx=e^y*y'y'(e^y-2xy)=y^2+cosxy'=(y^2+cosx)/(e^y-2xy)

y=f(x+sinx) 求y''.

y'=f'(x+sinx)(1+cosx)y''=f''(x+sinx)(1+cosx)^2+f'(x+sinx)(1-1/1+x^2)=f"(x+sinx)(1+cosx)^2+f'(x+sinx)