x的平方-2xy y的平方-5y-6十字相乘
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(1)x的平方-y的平方+4x+4y=(x+y)(x-y)+4(x+y)=(x+y)(x-y+4)(2)x的平方*y的平方+1-x的平方-y的平方=x²y²-x²+1-y
x^2=x的平方‘/’为除以[(x+2y)^2-(x+y)(x-y)-5y^2]/(2x)=[(x^2+4xy+4y^2)-(x^2-y^2)-5y^2]/(2x)=[4xy]/(2x)=2y[(3x
x平方+3y平方-2等于8x²+3y²-2=8两边同时乘以55x²+15y²-10=405x²+15y²=505x平方+15y平方+215x
Y^2(2X+1)(X-3)
先将96=3*2*2*2*2*2然后组合成12*8=96xxy+yyx=xy(x+y)=12*8=2*6*(2+6)=12*8=96x=2,y=6xx+yy=2*2+6*6=4+36=40
2x(-xy)^2-x^2(x^2y^2-y^2)=(xy)^2(2x-x^2+1)
题目没有说明是化简还是分解因式,如果是化简的话,就是:7(x+y)²-5(x+y)²-2(x+y)=2(x+y)²-2(x+y)=2(x²+2xy+y²
题目是√x^3+X^2y+1/4xy+√(1/4x^3)-X^2y+xy^2如果是:√x^3+X^2y+1/4xy+√(1/4x^3)-X^2y+xy^2=(3/2)√x^3+xy/4+xy^2=(3
((x-y)(x-y))/((x-y)(x+y))=(x-y)/(x+y).
原式=-2x²y^6+20x²y³再问:还在吗再答:嗯有新的题请采纳我,重新问再问:(x+3y)(2x-y)谢谢再答:采纳我,重新问
x的平方乘y的平方-4-2x的平方乘y的平方=-x的平方乘y的平方-4
∵4x²-y²+2x-y=(2x-y)(2x+y)+(2x-y)=(2x-y)(2x+y+1)∴4x²-y²+2x-y=(2x-y)(2x+y+1)不懂得欢迎追
a(x²+2xy+y²)-b(x²-y²)=a(x+y)²-b(x+y)(x-y)=(x+y)(ax+ay-bx+by)再问:你确定对吗?和我已开始算
x^2+y^2-2x-4y+5=0(x^2-2x+1)+(y^2-4y+4)=0(x-1)^2+(y-2)^2=0∴(x-1)^2=0(y-2)^2=0∴x-1=0x=1∴y-2=0y=2所以x=1,
x的平方+y的平方-2x+4y=-5x²-2x+1+y²+4y+4=0﹙x-1﹚²+﹙y+2﹚²=0x-1=0,y+2=0x=1,y=-2
x的平方-x-4y的平方+2y=(x-2y)(x+2y)-(x-2y)=(x-2y)(x+2y-1)
原式=5x^2-2(3y^2-5x^2)+(-4y^2+7xy)=5x^2-6y^2+10x^2-4y^2+7xy=(1+10)x^2-(6+4)y^2+7xy=11x^2-10y^2+7xy
由x-2y=0得x=2y,x²=4y²,当x,y都不为0时,(2x²-3y²)/(x²+5y²)=(8y²-3y²)/(
(x平方+2xy+y的平方)/(x+y)=(x+y)²/(x+y)=x+y
(3x-y)的平方-(2x+y)的平方-5(x-y)=(3x-y+2x+y)(3x-y-2x-y)-5(x-y)=5x(x-2y)-5(x-y)=5x^2-10xy-5x+5y