x减x分之1等于2,求x的2次方加x2次方分之1的值-搜答案-搜搜考试网

2分之1x减3分之1x等于6分之56分之5x=6分之5x=6分之5÷6分之5x=1再问：是减不是加再答：2分之1x减3分之1x等于6分之56分之1x=6分之5x=6分之5÷6分之1x=5

（x+1）/x²-2x²/(x+1)=1两边乘x²(x+1)(x+1)²-2x^4=x²(x+1)x²+2x+1-2x^4=x^3+x

x^2-3x+1=0x^2+1=3x两边同除以xx+1/x=3x^2+1/x^2=(x+1/x)^2-2=9-2=7x^4+1/x^4=(x^2+1/x^2)^2-2=49-2=47

X=2,y=1/2;(X+y)*(x+y)=(5/2)*(5/2)=25/4(x-y)*(x-y)=(3/2)*(3/2)=9/41/4*1*1-(3y)*(3y)=1/4-9/2=-17/4最终结果

x^2-3x+1=0x+1/x=(x^2+1)/x=(x^2-3x+1+3x)/x=(0+3x)/x=3x^2+1/x^2=(x+1/x)^2-2=3^2-2=7

x²-5x+1=0x²+1=5x两边除以xx+1/x=5两边平方x²+2+1/x²=25x²+1/x²=23x²+1/x²

3^(x+1)2^x-3^x2^(x+1)=363×3^x2^x-2×3^x2^x=366^x=366^x=6²x=2

2^x-1/(2^|x|)=2,将2^x看成整体xx=2^x,两边同乘xxxx^2-2xx-1=0得到xx =1 - Sqrt[2]（舍去）, xx

x^2-2x-1=0x=1±√2,x=1-√2x+1/x=1-√2+1/(1-√2)=1-√2-(1+√2)=-2√2

有两种情况：一种(x-2)=1即x=3一种x+3=0即x=-3

因为：x(x+1)(x+2)(x+3)=x(x+3)(x+1)(x+2)=(x²+3x)(x²+3x+2)而因为x=(√5-3)/2代入x²+3x得x²+3x=

由x²-x+1分之x等于2得：x分之x²-x+1等于2分之1即：x-1+1/x=1/2x+1/x=3/2(x+1/x)^2=9/4x^2+2+1/x^2=9/4x^2+1+1/x^

2^x=1/322^x=(1/3)^52^x=2^(-5)x=5(1/3)^y=81(1/3)^y=3^4(1/3)^y=(1/3)^(-4)y=-4x^y=5^(-4)=1/(5^4)=1/625很

额,这个好象是等于0

x-(1/x)=2两边平方x²+(1/x²)-2=4x²+(1/x²)=4+2=6x²+(1/x²)=6两边平方x^4+(1/x^4)+2=

2^(2x+3)-2^(2x+1)=1928*2^(2x)-2*2^(2x)=1926*2^(2x)=1922^(2x)=322x=5x=5/2

(x^2-1)/2-(x-2)/3=x^23x^2-3-2(x-2)=6x^23x^2-3-2x+4=6x^23x^2+2x-1=0(3x-1)(x+1)=0所以x=1/3或x=-1

等式两边同乘以12,得：12x-2x-1=12-9x+6化简,得19x=19x=1

已知2的2x+3次方-2的2x+1次方=192,求x的值.2^(2x+3)-2^(2x+1)=1922^(2x+1)(2^2-1)=1922^(2x+1)=64=2^62x+1=6x=2.5

(x-1)(x-3)(x-4)(x-5)-(x-1)(x-2)(x-3)(x-5)=(x-1)(x-2)(x-4)(x-5)-(x-1)(x-2)(x-3)(x-4)(x-1)(x-3)(x-5)(x