x-3分之3-x的平方-9分之18-搜答案-搜搜考试网

原式=(x-3)^2)*[(x+3)/(x-3)(x-6)]=(x+3)(x-3)/(x-6)=(x^2-9)/(x-6)

x的平方-9分之x的平方-4x+4除以x的平方+3x分之x的平方-4除以x的平方=（x-2）²/(x+3)(x-3)÷（x+2）(x-2)/x(x+3)÷x²=（x-2）（x+2）

题意是这样的吧：求(x²+9x)/(x²+3x)+(x²-9)/(x²+6x+9)原式=(x²+9x)/(x²+3x)+(x+3)(x-3)

是求X的值吗?不晓得对不对哈,姑且一看吧　　由已知可得：

X的平方+3X分之X的平方+9X+X的平方+6X+9分之X的平方-9=x（x＋3）分之（x²＋9x）＋（x＋3）²分之（x＋3）（x-3）==x（x＋3）分之（x²＋9x

=(x+2)(x-1)/(x-3)×(x-3)²/(x+2)=(x-1)(x-3)=x²-4x+3

1/3[1/x--1/(x+3)]+1/3[1/(x+3)--1/(x+6)]+1/3[1/(x+6)--1/(x+9)]=1/(x^2+18)1/x--1/(x+9)=3/(x^2+18)(x+9)

x-3分之5-x方-9分之x-2+2x-6分之x-1=5/(x-3)-(x-2)/(x^2-9)+(x-1)/2(x-3)=(10(x+3)-2(x-2)+(x-1)(x+3))/2(x+3)(x-3

[(x的平方-3x)分之(x+3)-(x的平方-6x+9)分之(x-1)]÷x分之(x-9)=[(x+3)/(x^2-3x)-(x-1)/(x^2-6x+9)])]÷[(x-9)/x]=[(x+3)/

1：2分之3X的平方-{-2分之1X平方}+{-2X平方}=3x²/2+x²/2-2x²=4x²/2-2x²=2x²-2x²=02

原式=(x-3)/(x²+x)*1/(x-3)²约去x-3=1/[(x-3)(x²+x)]=1/(x³-2x²-3x)

x的平方-2x+1分之x-3÷x-1分之x的平方-9=[(x-3)/(x-1)²]*[(x-1)/(x+3)*(x-3)]=1/(x-1)(x+3)

[(x+3)/x(x-3)+(x-3)/(x-3)²】×[-(x-3)/x]=(x+3+x)/x(x-3)×[-(x-3)/x]=(2x+3)/x²

(x²+6x+9)分之(x-3)+(9-x²)分之x=(x²+6x+9)分之(x-3)-(x²-9)分之x=(x+3)²分之(x-3)-[(x+3)(

原式=x(x-9)/x(x+3)-(x+3)(x-3)/(x-3)²=(x-9)/(x+3)-(x+3)/(x-3)=(x²-12x+27-x²-6x-9)/(x+3)(

原式=1/(x+1)*[(x-3)/(x+3)^2+2/(x+3)]-x/(x+3)(x-3)=1/(x+1)[3(x+1)/(x+3)^2]-x/(x+3)(x-3)=3/(x+3)^2-x/(x+

x分之x-3*9-x的平方分之x=（x-3）/x*x/(3-x)(3+x)=-(x+3)=-x-3

=(x+2)/(x-3)×(x-3)²/(x+2)(x-2)=(x-3)/(x-2)

x+x分之1=3所以x0X^2-3X+1=0X=(=(3+根号下5)/2或=(3-根号下5)/2x的平方+9x-3分之x的平方=2/3X^2+9x把X^2=1-3x代入得2/3-2X+9x=2/3+7

原式=1/(x-3)-1/2(x+3)-x/(x-3)²=[2(x+3)(x-3)-(x-3)²-2x(x+3)]/[2(x+3)(x-3)²]=(2x²-18