x-2y分之x-y除以x平方-4xy 4y平方分之x平方-y平方-搜答案-搜搜考试网

（xy分之X的平方-Y的平方）的平方除以【（X+Y）*（X分之X-Y）的3次方]除以y的平方分之x=[（x^2-y^2)^2/x^2y^2]÷[x^2-y^2)(x-y)^2/x]^3÷（x/y^2)

①-x+2y分之x-y除以x的平方+4xy+4y的平方分之x的平方-y的平方=-(x-y)/(x+2y)÷(x^2-y^2)/(x^2+4xy+4y^2)=-(x-y)/(x+2y)×(x^2+4xy

1-（x-y）/(x+2y)÷(x²-y²)/(x+2y)²=1-(x-y)/(x+2y)×(x+2y)²/(x+y)(x-y)=1-(x+2y)/(x+y)=

3x^2+xy-2y^2=(3x-2y)(x+y)=0x=-2y/3,或x=-y但由于你要求的式子中分母里有X平方-Y平方x=-y舍去其他就代入吧

x^2=x的平方‘/’为除以[(x+2y)^2-(x+y)(x-y)-5y^2]/(2x)=[(x^2+4xy+4y^2)-(x^2-y^2)-5y^2]/(2x)=[4xy]/(2x)=2y[(3x

【x-y-(x-y分之4y平方)】【x+y-(x+y分之4x平方)】除以【3(x+y)-x-y分之8xy】=（x-y-x+4y)(x+y-x-4x/y)/(3x+3y-x-8x)=3y*(y-4x/y

做这样的题要会把分子分母分解因式,最好分解完.这需要有扎实的分解因式的功夫,看到像x^2-y^2这样的式子要敏感,给你几个等式要会把它们用活：x^2-y^2=(x+y)(x-y),x^3-y^3=(x

=(xy-x的平方）除以(x的平方-2xy+y的平方\xy)乘以(x-y\x的平方)=-x（x-y）×xy/（x-y）2×（x-y）/x2=-y再问：嗯

x平方+y平方+2xy分之x平方-4y平方除以x平方+xy分之2y+x=(x-2y)(x+2y)/(x+y)²·x(x+y)/(x+2y)=x(x-2y)/(x+y)

原式=[2x/(x-y)]*[y/(x+y)]-[x^4/(x^4-y^4)]/[x^2/(x^2+y^2)]^2=2xy/(x^2-y^2)-(x^2+y^2)^2/[(x^2+y^2)(x^2-y

x(y-x)÷(x²-2xy+y²)/xy×(x-y)/x²=-x(x-y)×xy/(x-y)²×(x-y)/x²=-y

(x^2-4y^)\(x+y)^2乘以2x(x+y)/(x+2y)=2x(x-2y)\(x+y)

[1/(x-y)-1/(x+y)]/[xy^2/(x^2-y^2)]=[(x+y-x+y)/(x-y)(x+y)]/[xy^2/(x-y)(x+y)]=[2y/(x-y)(x+y)]/[xy^2/(x

原式=[(x+y)/(x-y)]^2*[2(x-y)/5(x+y)-[X/(x^2y^2)]/[x/(x+y)]=2/5-[x/(x^2y^2)]*[(X+y)/x]=2/5-(x^2y^2)/(x+

能把等式照下来吗

adawdawdawd

【（x+2y）2-(x+y)(3x-y)-5y2】÷（2x）=[x^2+4xy+y^2-(3x^2+2xy-y^2)-5y^2]/(2x)=[-2x^2+2xy]/(2x)=y-x=1/2-2=-3/

(x+y)分之(x²-y²)×(x²+xy)分之(2x+2y)÷(x-y)=(x+y)分之[(x+y)(x-y)]×[x(x+y)]分之[2(x+y)]×(x-y)分之1