输入一个四位正整数,将其逆序输出.如:输入"1234",输出"4321"

intfun(intn){inta=n,b=0;while(a>0){b=b*10;b=b+a%10;a=a/10;}printf("%d",b);getch();return0;}或者把后三行删掉,

//z2.cpp:定义控制台应用程序的入口点.//#include"stdafx.h"#include#includeusingnamespacestd;voidReverse(int&m)//m为4

两个地方错了.第一,scanf()读入的应为变量的地址,所以scanf("&d",x);应该是scanf("%d",&x)  

intmain(){intn,n1,n2,n3,n4;cin>>n;n1=n/1000;n2=(n%1000)/100;n3=(n%100)/10;n4=n%10;n=n1+10*n2+100*n3+

#includevoidmain(){intx,a,b,c;scanf("%d",&x);a=x/100;b=x/10%10;c=x%10;x=c*100+b*10+a;printf("%d",x);

n=val(inputbox("请输入N"))t=1fori=1tonjc=1forj=1toijc=jc*jnexts=s+t*jct=-tnextprints第二题：DimxPicture1.Au

规定利用Mod跟“/”来编码廷垃圾的,本来两个函数就搞定了.PrivateSubCommand1_Click()DimaAsInteger,bAsInteger,cAsIntegerDimiAsInt

你写的实在是太繁琐了.这个是不可取的.你需要的这两个功能其实是可以一起实现的,虽然一楼说的很对,当我觉得应该不是你需要的那一种方案.#includemain(){inti=0,k;inta[10;pr

#include#includeintmain(){intoldnum;intnewnum=0;inttemp;printf("pleaseinputnumber\n");scanf("%d",&ol

#includeusingnamespacestd;voidmain(){intnum,reverse=0,count=0;while(1){coutnum;//输入数据if(cin.bad()||n

#includemain(){intn,i;inta[10];printf("请输入个数n:");scanf("%d",&n);for(i=0;i=0;i--)printf("%d\t",a[i]);

#includeintmain(void){longintx;inty,i=1;printf("请输入一个不超过100000的整数:");//99999||x

/*从键盘上输入一个任意位数的正整数,判断它是几位数,并逆序输出该数*/#include"stdio.h"intmain(){intnum,temp,i=0;printf("请输入一个数字\n");s

可以是可以,不过太麻烦了,见下面的代码#includeintmain(){inta,b[5],s=0;scanf("%d",&a);while(a){b[s++]=a%10;a/=10;}printf

PrivateSubCommand1_Click()d=Val(Text1)Print100*(dMod100)+Int(d/100)EndSu

#include"math.h"#includeusingnamespacestd;#defineM4voidmain(){intnum,p[M],i;cout

编程:输入一个3位正整数,正确分离出其个位、十位、百位数...一年四季行好运八方财宝进家门家和万事兴春雨丝丝润万物红梅点点绣千山春意盎然

#includevoidmain(){inti,n;printf("pleaseinputn:");scanf("%d",&n);printf("%d=",n);for(i=2;i

#include#defineMAXN20intmain(){intn,t,k=0;intia[MAXN];printf("请输入一个整数:");scanf("%d",&n);while(t=n%10

#include#defineNUM20voidmain(){longn;intdata[NUM]={0},len=0;scanf("%d",&n);do{data[len++]=n%10;n/=10