输入一个5*5的矩阵,除对角线上的元素为1外,其它数组元素的值为0

#include"stdio.h"#defineM5//矩阵阶数voidmain(){inta[M][M],i,j,sum=0;printf("请输入%d*%d矩阵：\n",M,M);for(i=0;

for(i=0;i=0;i--,j++)sum1=sum1+a[i][j];

intnSum=0;for(inti=0;i

#include"stdio.h"voidmain(){intmagic[5][5]={{17,24,1,8,15},{23,5,7,14,16},{4,6,13,20,22},{10,12,19,

#include"stdio.h"intmain(){inta[10][10]={0};intn,i,j,sum1=0,sum2=0;scanf("%d",&n);for(i=0;i

intmain(){inta[5][5],i,j,sum1,sum2;sum1=0;sum2=0;for(i=0;i

#include<cstdlib>#include<ctime>using namespace std;int main(){ sran

PrivateSubCommand1_Click()DimmArr(1To5,1To5),r%,c%,tmp%Forr=1To5Forc=1To5Randomizetmp=Int(Rnd*90)+10

我就用C语言吧.#includemain(){doublea[5][5]={0.0};inti,j;doubles=0.0;for(i=0;i

if(j==4)\x09\x09\x09\x09printf("%d\n",max);去掉if(j==4)加大括号.改成这样:#defineM3#defineN5#includevoidmain(){

#include<stdio.h>main(){\x05inta[100][100],i,j,n,A=1,B=1;\x05chart;\x05scanf("%d\n",

#includeusingnamespacestd;voidmain(){intCArray[5][5];inti,j;intsum=0;cout

//输入范例假设n赋值为4/*1234(回车)2345(回车)3456(回车)5678(回车)注意输入时数字间要有空格间隔*/#includevoidmain(){inti,j;intsum=0;//

#include#defineN6main(){inti,j,n=1,s=0,m=0,a[N][N];for(i=0;i

#includeintmain(void){inti,j,sum;inta[5][5];sum=1;for(i=0;i

//修改了一下,如下参考一下吧：#include#defineMAX100//定义一个最大的范围voidmain(){inta[MAX][MAX],n,i,j,sum=0;//原来这里数组定义不正确p

#include <stdio.h>void main(){\x05int i, j, array[5][5], sum=0;\

#include"stdio.h"#defineN10intmian(){inta[N][N];inti,j,sum=0;for(i=0;i

//zd_40.cpp:Definestheentrypointfortheconsoleapplication.//#includeintmain(intargc,char*argv[]){inti

#includevoidmain(){inta[5][5]={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25},i,