设2x-tan(x-y)=-搜答案-搜搜考试网

左右对x求导有y'/y=sec²(xy)(y+xy')整理有y'=y²/(cos(xy)-xy)所以dy=(y²/(cos(xy)-xy))dx

题目不全已知tan(x+y)=2/5,tan(y-π/4)=1/4,求tan(x+π/4)的值解令a=x+y,b=x+π/4tan(x+π/4)=tan[(x+y)-(y-π/4)]=tan(a-b)

kπ-π/2

tanx属于实数R设t=tanxy=t^2+t+1=(t+1/2)^2+3/4所以函数值域是[3/4,正无穷）tanx=1,(-TT/2,TT/2)和(0,2TT）X的值(-TT/2,TT/2)里,x

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=(secX+tanX)'/(secX+tanX)=(secxtanx+sec²x)/(secX+tanX)=secx(tanx+secx)/(secX+tanX)=secx

tan,正切；sin,正弦；cos,余弦tan(x+y)tan(x-y)=sin(x+y)/cos(x+y)*sin(x-y)/cos(x-y)=sin(x+y)sin(x-y)/[cos(x+y)c

tanx函数的周期是π,所以y=tan(2x-3）的周期等于π除以2=π/2

先把角度转成弧度x=-74;y=-27;a=x*pi/180;b=y*pi/180;这样就可以直接在命令提示符下输入式子计算了sin(a^2+b^2)/(sqrt(tan(abs(a+b))+pi))

sin(2a+b)=3sinbsin[(a+b)+a]=3sin[(a+b)-a]sin(a+b)cosa+cos(a+b)sina=3[sin(a+b)cosa-cos(a+b)sina]sin(a

求导 y=ln(tan(x/2))

y'=1/(tan(x/2))*(tan(x/2))'=1/(tan(x/2))*(sec^2(x/2))*(x/2)'=1/(2sin(x/2)*cos(x/2))=1/sin(x)=csc(x)

sin(2α+β)=sin(2α)cosβ+cos(2α)sinβ=3sinβsin(2α)+cos(2α)tanβ=3tanβ[3-cos(2α)]tanβ=sin(2α)tanβ=sin(2α)/

2x-tan(x-y)=∫(0,x-y)[sec（t）]^2dt两边对x求导得：2-sec²(x-y)(1-y')=sec²(x-y)(1-y')sec²(x-y)(1-

设tan(180-x)=2,-90

由TAN(180-X)=2得tanx=-2,所以,-90

kπ-π/2

（线性规划）由条件当X=Y=3时有最大值Z=6即得K=3再由X+2Y>=0很容易求得Z最小值-3

函数y=tan^2(x)-2tan(x),＝（tanx-1)^2+1-60°

y′=y/x+tan[(y/x)^2]

设一个变量u=y/x,带入方程很好求解,解不出来再联系我哈

（1）由sin（2α+β）=3sinβ，得sin[（α+β）+α]=3sin[（α+β）-α]，sin（α+β）cosα+cos（α+β）sinα=3sin（α+β）cosα-3cos（α+β）sin

1.y=(tan^2x-csc^2x)/(tan^2x+cot^2x-1)=(sin^2x/cos^2x-1/sin^2x)/(sin^2x/cos^2x+cos^2x/sin^2x-1)=(sin^