若函数f(x)=3cos(wx &)对任意实数x

a=-π/6

f(x)=sinwxcosPai/3+coswxsinPai/3-coswxcosPai/6+sinwxsinPai/6+coswx=sinwx+coswx=根号2sin(wx+Pai/4)T=2Pa

f(x)=sin(wx+阿发)+cos(wx+阿发)=√2[√2∕2sin(wx+阿发)+√2∕2cos(wx+阿发)]（提取√2,根号2）=√2[cos45°sin(wx+阿发)+sin45°cos

f(x)=sin(wx+φ)-cos(wx+φ)=√2[√2/2sin(wx+φ)-√2/2cos(wx+φ)]=√2sin(wx+φ-π/4)∵函数y=f(x)图像的两相邻对线轴的距离为π/2.∴f

1)∵cos(wx+π/3)+cos(wx-π/3)=coswxcosπ/3-sinwxsinπ/3+coswxcosπ/3+sinwxsinπ/3=coswxf(x)=根号3sinwx+cos(wx

(1)sin(wx+π/6)=sinwxcosπ/6+coswxsinπ/6sin(wx-π/6)=sinwxcosπ/6-coswxsinπ/6f(x)=sin(wx+π/6)+sin(wx-π/6

f(x)=2cos^2wx/2+cos(wx+π/3)=(1+coswx)+cos(wx+π/3)=1+coswx+coswxcos(π/3)-sinwxsin(π/3)=1+(3/2)coswx-(

（1）f(x)=√3sinwxcoswx-cos²wx+1/2=√3/2sin2wx-1/2cos2wx=sin(2wx-π/6)∵图像两相邻对称轴的距离为π/4∴T/2=π/4∴T=π/2

1.f(x)=根号3sin(wx+a)-cos(wx+a)当a+π/3=kπ时f(x)为偶函数,而0<a<π,则a+π/3=πf(x)=2coswx,而函数y=f(x)图象的两相邻对称轴间

(1)f(x)=根号3sin(wx+φ)-cos(wx+φ)=2Sin(wx+φ-π/6)由于是偶函数,即f(x)=f(-x）即2Sin(wx+φ-π/6)=2Sin(-wx+φ-π/6)即Sinwx

f(x)=sin(wx+φ)+cos(wx+φ)=√2sin(wx+φ+π/4)T=2π/w=πw=2f(x)=√2sin(2x+φ+π/4)f(-x)=f(x),所以f(-π/8)=f(π/8)si

（1)f(x)=根号3sin(wx+φ)-cos(wx+φ)=2Sin(wx+φ-π/6)由于是偶函数,即f(x)=f(-x）即2Sin(wx+φ-π/6)=2Sin(-wx+φ-π/6)即Sinwx

已知函数f(X)=sin^2wx+根号3sinwx*sin(wx+π/2)+2cos^2wx,x属于R,在y轴右侧的第一个最高点的横坐标为π/6,求w；若将函数f(x)的图像向右平移π/6个单位后,再

首先f(-x)=f(x),得出是关于Y轴对称,f(0)要不是最大值,要不是最小值,排除B,D因为g的绝对值小于n/2,n就是PAI,所以单从SIN和COS上考虑,SIN移动一个正数（这个正数小于n/2

你一开始就算错了f(x)=√3*cos（2x+π/6）+1后面的应该会算了吧再问：。。。。还是不会、具体怎么做的再答：将f(A)==1/2代入上式求得A=π/3然后用S=bc*sinA求得b=2最后用

是f(x)=2cos²(ωx/2)+cos(ωx+π/3)-1吧?如是,则：（一）f(x)=cosωx+cos(ωx+π/3)=(3/2)cosωx-(√3/2)sinωx=√3cos(ωx

f(x)=2[sin(wx+β)cosπ/6-cos(wx+β)sinπ/6]=2sin(wx+β-π/6)相邻对称轴距离是半个周期所以T=π2π/w=πw=2偶函数则x=0是对称轴,所以x=0wx+

已知函数f(x)=(√3)sin(ωx+φ)-cos(wx+φ)(0

(1)f(x)=√3sin(wx+φ)-cos(wx+φ)=2sin(wx+φ-π/6)相邻对称轴间的距离为π/2,最小正周期为π所以w=2π/π=2又知f(0)=2sin(φ-π/6)=00