matlab z=0:0.01:4-搜答案-搜搜考试网

y=x^5+4sinxdy=(5x^4+4cosx)dxx=0.dx=0.01dy=4(0.01)=0.04

clear,clctheta=0:0.01:2*pi;t1=legendre(1,cos(theta));h=t1(1,:)./sin(theta);plot(theta,h)再问：牛人！能做真实的有

x的取值是离散的,每一步增加0.01,即x(k+1)=x(k)+0.01;其中起始值为0,终值为2*3.14.

先取(3,4)因为3^2=94^2=16再取(3,3.5)3.5^2=12.25再取(3,3.25)3.25^2=10.5625再取(3,3.125)3.125^2=9.765625再在3.125和3

x1=0.62x2=-1.62

刚才编写的,希望对你有所帮助.symsxforz=0:0.01:2y1=x+z;ezplot3(x,y1,z,[-inf,1]);holdon;y2=1+z;ezplot3(x,y2,z,[1,2])

2t+1/2×0.01×t^2=3t1/2×0.01t^2+2t-3t=01/2×0.01t^2-t=00.01t^2-2t=0

theta为0到2pi,步长（间隔）是0.01,然后本来是一行向量的,加了“'”后,变成列向量了.

0.01代表步长,也就是把区间（0,2*pi）按0.01分开,步长越小,MATLAB绘制出来的图像光滑度越好

z=1:0.001:15;wt=10^16;wt=wt-floor(wt/(2*pi))*(2*pi);Ex=cos(wt-2*z+0);Ey=cos(wt-2*z+1.57);plot3(z,Ex,

90.02=多少个0.01

9002

x²=0.01x=-0.1,x=0.116x²-25=0x²=25/16x=-5/4,x=5/48x³=-125x³=-125/8x=-5/2

x=0:0.01:100因为x定义成了矩阵,^这个符号就不对了,其实算y的时候就是矩阵的幂了,用power函数吧x=0:0.01:100;y=power(2,x);plot(x,y)可画出图

(0.064)-13-(-78)0+[(-2)3]-43+log28+|-0.01|12=(0．43)-13-1+(-2)-4+3+(0．12)12=0．4-1-1+116+3+0.1=52-1+11

0.25x^2-0.01=0 咋算?

0.25x^2-0.01=00.25x²=0.01x²=0.01/0.25x=0.1/0.5或x=-0.1/0.5x=1/5或x=-1/5很高兴为您解答,【the1900】团队为您

0.5分之（0.3x-0.2）-0.03分之（0.02+0.01x）=0（3x-2)/5-(2+x)/3=03（3x-2)-5(2+x)=09x-6-10-5x=04x=16x=4

时间长度为0.01秒,采样间隔1/Fs

0.7除于0.01=

同时扩大100倍,就是70÷1＝70

=1/3*(54+6*87^(1/2))^(1/3)-2/(54+6*87^(1/2))^(1/3)=1.1795

（0.3x-0.2)/0.5-(0.02+0.01x)/0.03=0(3x-2)/5-(2+x)/3=03(3x-2)-5(2+x)=09x-6-10-5x=04x=16x=4