编程输俩个正整数m和n,计算它们的最大公约数和最小公倍数

输入两个正整数m和n,求其最大公约数和最小公倍数.用辗转相除法求最大公约数算法描述:m对n求余为a,若a不等于0则m0){m_cup=m;n_cup=n;res=m_cup%n_cup;while(r

从上而下依次填空,VC测试通过了：intc[ROW][ROW]c[i][j]=0;c[i][j]=c[i][j]+(a[i][k]*b[k][j]);printf("\n");&a

#include<stdio.h>#include<math.h>int min(int x,int y)\x09\x09//求m和n的最小值{\

#includeintmain(){intm,n;intm_cup,n_cup,res;/*被除数,除数,余数*/printf("Entertwointeger:\n");scanf("%d%d",&

#include int main() { int m, n; int m_cup, n_cup, 

main(){inta,b,num1,num2,temp;printf("请输入两个正整数:\n");scanf("%d,%d",&num1,&num2);if(num1

#includevoidmain(){intn;ints=0;printf("请输入一个正整数：");scanf("%d",&n);printf("该整数除1和其本身的因子为：\n");for(int

利用辗除法公约数,再算公倍数.#include <stdio.h>void main(){    int a,&nbs

#include#includeusingnamespacestd;intmain(){intm,n,m_cup,n_cup,res;cin>>m>>n;if(m>0&&n>0){m_cup=m;n_

#includeintGcd(intm,intn)/*最大公约数*/{intt;if(m

#include#includevoidmain(){intm,n,i,j,mn,a,x,y;printf("请输入m,n\n");scanf("%d%d",&m,&n);mn=m*n;a=(mn)?

PrivateSubCommand1_Click()DimmAsLong,nAsIntegerm=Val(InputBox("请输入一个数"))Forn=1TomIf2^n>=mThenMsgBox"

importjava.util.*;publicclassTest40014{publicstaticvoidmain(String[]args){Scannerin=newScanner(Syst

#includeintmain(void){intn;inti;doublesum=0.0;intfact=1;scanf("%d",&n);for(i=1;i

#include#includeintmain(void){intn,m,i,j,t;scanf("%d%d",&n,&m);i=m>n?m:n;j=m>n?n:m;while(j){t=i%j;i=

#includeintmain(){intm,n;intsum1=0,sum2=0;scanf("%d%d",&m,&n);for(inti=m;i

最大公约数:intGcd(inta,intb){if(a%b==0)returna;return(b,a%b);}最小公倍数:intGbs(inta,intb){returna*b/Gcd(a,b);

#includeintFun(intn){inti,c=1;for(i=1;i

DimmAsInteger,nAsIntegerPrivateSubCommand1_Click()m=Val(InputBox("输入正整数"))n=Val(InputBox("输入正整数"))If

#includeintfact(intn){intt=1;for(inti=1;i