编写程序,根据输入的一元二次方程的系数求方程的根

#include#includemain(){floatx,y;scanf("%f",&x);if(x

#includemain(){intt;intis(intt);printf("输入年份为");scanf("%d\n",&t);t=is(t);if(t=1)printf("%d是闰年",t);el

double x1 = 0;//解1double x2 = 0;//解2Console.WriteLine("求 ax^

希望有用,敬请采纳^_^#include#includeintmain(){voidroot2(doublea,doubleb,doubledisc);//定义方程有两个根时的函数voidroot1(

varn:real;beginreadln(n);writeln('n的平方:',sqr(n):0:6);writeln('n的平方根:',sqrt(n):0:6);writeln('n的3次方根:'

#include#includevoidmain(){doublex;doubley;coutx;if(-2

解题思路：分解因式法可解。解题过程：varSWOC={};SWOC.tip=false;try{SWOCX2.OpenFile("http://dayi.prcedu.com/include/read

//Equation.h#ifndef_Equation_h#define_Equation_hclassEquation{private:doublea;doubleb;doublec;voidSh

对于ax^2+bx+c=0intpanduan(inta,intb,intc){intm;m=b*b-4*a*c;return(m);}voidmain(){inta,b,c,flag,x1,x2,t

请编写一个程序,从键盘输入100名职工的职工号、姓名和工资,输出所有职工的#include

PublicClassForm1PrivateSubButton1_Click(ByValsenderAsSystem.Object,ByValeAsSystem.EventArgs)HandlesB

#includepower(floata,floatb){floatsum1=a*b;returnsum1;}intmain(){floatx,y;floatsum;printf("inputthef

请参考

INPUTxa=xMOD2IFa=0THENPRINT"x是偶数"ELSEPRINT"x是奇数"ENDIFEND

第二题：#includevoidmain(){inti,g,s,b;for(i=100;i

C++的代码：#include#includevoidmain(void){doublea,b,c,d;charch('y');do{coutb>>c;if(-0.0001

std::stringf(intscore){if(score>=90)return"优";elseif(score>=80)return"良";elseif(score>=60)return"中";

dimaasdouble,basdouble,casdoubledimx1asdouble,x2asdoublea=val(inputbox(""))b=val(inputbox(""))c=val(

使用什么VB的话是INPUTNIFN\2=0THENPRINT'是'ELSEPRINT'否'ENDIFEND

#includemain(){doublea,b,z,c;cin>>a>>b;//输入长和宽z=a*b;//计算面积c=2*(a+b);//计算周长cout