编写求圆的面积的函数,并调用该函数
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#includedoublefun(doublex,doubley){returnx*x*x+y*y*y;}voidmain(){doublea=fun(3.4,2.8);doubleb=fun(10
main(){ints;s=getfactorial(6)+getfactorial(10)+getfactorial(20)printf("s=%d",s);}intgetfactorial(int
#include"stdio.h"voidmax_min(inta[],intn,int*max,int*min){int*p;*max=*min=*a;for(p=a+1;pif(*p>*max)*
#includedoublecalRectArea(doubledWidth,doubledHeigh){returndWidth*dHeigh;}voidmain(){doublea,b,mul;s
PrivateFunctionSUM(Fir_LAsDouble,Fir_SAsDouble,Scend_LAsDouble,Scend_SAsDouble)AsDoubleSUM=Fir_L*Fir
Bigger(inta,intb){returna>b?a:b;}Biggest(inta,intb,intc){returnBigger(a,b)>c:Bigger(a,b):c;}
#include<stdio.h>#include<stdlib.h>#define Pi 3.14159double square(double
先定义数组ainti=0;intj=0;doublepa=0;for(i=0;i再问:能不能来个完整版的,我一窍不通,谢谢了,再答:c语言或者c++么?再问:是的,c++再答:先采纳吧,十五分钟给你,
#include#includeintmax(inta,intb){if(a>b)returna;if(a
#includevoidfun(int*a,int*b){inttemp;temp=*a;*a=*b;*b=temp;}main(){inta=1;intb=2;fun(&a,&b);printf("
sum(n){intsum,i;if(i=1;i
==||童鞋.你是要返回输入的n个数的最大值,还是一个数组的最大值啊.返回输入n个数最大值的函数:#includeintMax(intn);//最大值函数声明intmain(){intn;scanf(
#includeintfact(int);main(){inti,sum=0;for(i=1;i
#include#includeboolisPrime(intnum){if(num!=2&&num%2==0)//除2以外的偶数都不是素数{returnfalse;}for(inti=3;i
#include#includeusingnamespacestd;intjust(intnum){for(inti=2;i
#include#includevoidb1(){floatl,s,k;inta,b,c,h;printf("\n");printf("\n");printf("输入a,b,c的值\n");print
#includeintmaxy(int&a,int&b){intn,i,j;for(i=1;i>x>>y;s=maxy(x,y);cout
PublicFunctiontrangle(aAsDouble,bAsDouble,cAsDouble)AsDoubleIfa+bDimsAsDoubles=0.5*(a+b+c)a=s-ab=s-b
voids(folata,folatb,folatc){folatp;p=(a+b+c)/2;S=√[p(p-a)(p-b)(p-c)];returns;}
//今天被百度吞了4份代码,上帝保佑这个别被吞了,哥的分数啊.#includeintmain(){intn,i,j;scanf("%d",&n);for(i=1;i