编写求两个数的和,差及平均值的三个函数,在主函数中调用并求出结果

是前n个元素么?main(){inti=n,sum=0;max=a[0];min=a[0];for(i=0;ia[i])?max:a[i];min=(min再问：输出的avg不是整数再答：哎呀，忘了这

这个简单：#includeusingnamespacestd;intHe(intx,inty){intz;z=x+y;returnz;}intCha(intx,inty){intz;z=x-y;ret

给你个思路吧,写个平方出来,后面的自己模仿//求两个数的平方,成功返回0,不成为返回-1.intfunction(double*pNum1,double*pNum2){if(NULL==pNum1||

输入两个整数,中间空格：#include<stdio.h>main(){\x09int a,b;\x09printf("Input a,b:\n")

#include"stdio.h"main(){floata[20],avg=0.00;inti;printf("Pleaseinputdatas!\n");for(i=0;i

#include <stdio.h> int main (){      int&nbs

调试过了,如果需要小数,把int换成float就行了#include"stdio.h"intSub(inta,intb){intc=a-b;returnc;}intmain(){inta,b;prin

importjava.util.Scanner;publicclassTest{publicstaticvoidmain(String[]args){Scannersc=newScanner(Syst

doublefun(doublea,doubleb,intop){switch(op){case1:returna+b;break;case2:returna-b;break;case3:return

#include“stdio.h"voidmain(){\x09inta,b,c,sum;\x09floatave;scanf("%d%d%d",&a,&b,&c);sum=a+b+c;\x09ave

Private Sub Command1_Click()Dim i As Integer, j As Integer,&

//以下是用C语言写的unsignedinta,b;unsignedintsum;//求和unsignedintadd(inta,intb){return(a+b);}//差unsignedintde

x+y=35x-y=10x=22.5y=12.5

#includevoidmain(){doublea,b;printf("请输入两个数a,和b\n");scanf("%lf%lf",&a,&b);printf("两个数和是:%lf\n",a+b);

PrivateSubCommand1_Click()a=InputBox("请输入数字","提示")b=InputBox("请输入数字","提示")Print"和："&Val(a)+Val(b)Pri

=AVERAGE(B5,VALUE(B6),VALUE(B7),VALUE(B8))

x+y+x-y+xy+x/y=362x+xy+x/y=36x/y*(y+1)^2=36注意到和差积都是整数,所以商也是整数,所以x/y和y+1都是36的约数36=1*36=4*9=9*4=36*1x=

#include#includevoidmain(){inta[10];intsum=0;intbelow_ave=0;floatave=0;inti;printf("inputteninteger:

data=[];%初始数据为空in=input('输入:');%输入一个数据while(isempty(in)||in~=0)%空数据或者数据不为0进入循环,数据为0跳出循环data=[datain]

#include"stdio.h"voidzuizhi(floatb[],intn,floatmax,floatmin,floataver);voidmain(){floata[2],max,min