编写一个递归函数,计算并返回斐波那契数列中第n项的值,-搜答案-搜搜考试网

#includeintdigit(intn,intk){returnk>1digit(n/10,k-1):n%10;}intmain(){printf("%d",digit(12345,3));}

#include"stdio.h"intisprime(inta){intj;for(j=2;j

帮你写好了.unsigned int fib(unsigned int n) {\x09if (n == 1

#includelongintf(intn){if(n==0)return0;elseif(n==1)return1;elsereturnf(n-1)+f(n-2);}intmain

// C++int F(int n) {if (n == 0) return 1;else if

function[xmax,xmin]=xsort(x)x=sort(x);xmax=x(end)xmin=x(1)再问：不对啊。显示出这个???StringspassedtoEVALcannotco

#includedoubleH(intn,doublex){if(x>1){if(n==0)return1.0;//H0(x)=1;if(n==1)return2.0*x;//H1(x)=2x;//直

#includeintFibonacci(intn){if(n==1||n==2)//递归结束的条件,求前两项return1;elsereturnFibonacci(n-1)+Fibonacci(n-

我有我给你.

#includelongfac(intn){inti;longx=1;for(i=2;i再问：谢谢咯！可是我说的是递归法哦！再答：#includelongfac(intn){if(n==0)retur

C描述functionttt(n){ returnn>1?n*ttt(n-1):1;}使用方法:ttt(21);

#include<stdio.h>unsignedlongcombinNum(intm,intn){ inti; unsignedlongx=1; if(n&

#includeintfact(int);main(){inti,sum=0;for(i=1;i

intSumNums(intnum){if(num

#include"stdio.h"intsum(intn);main(){inti,n,s=0;printf("Inputn:");scanf("%d",&n);printf("%d\n"

#includeintfibo(intn){if(nreturn1;elsereturnfibo(n-1)+fibo(n-2);}intmain(){intn;scanf("%d",&n);print

intsum(intn){ints=0;inti=1;boolflag=true;for(;i再问：boolflag=true;什么意思啊，不对的啊再答：C语言中的布尔型，不是bool吗？那你试试bo

static int reverse2(int num, int t){ if (num&nb

#include <iostream>using namespace std;long fact(int n){ &

用递归法计算n!用递归法计算n!可用下述公式表示：n!=1(n=0,1)n×(n-1)!(n>1)按公式可编程如下：longff(intn){longf;if(n