编写一个shll脚本求斐波那契数的前十项及总和

#!/bin/bashi=1j=0for((k=0;k

viewplaincopytoclipboardprint?publicclassFibonacci{/***@paramargs*/publicstaticvoidmain(String[]args

#!/bin/bashforiin$(seq10)doecho$((i*i))doneexit0

为用了很没有效率的递归,所以出结果有点慢#includeiostream.h

#includelongintfn(int);voidmain(){printf("%d",fn(10));}longintfn(intm){longinttemp;if((1==m)|(2==m))

因为用了很没有效率的递归,所以出结果有点慢#includef(int);main(){inti,s=0;for(i=1;i

PrivateFunctionF(nAsLong)AsLongIfn>2ThenF=F(n-1)+F(n-2)ElseF=1EndIfEndFunctionPrivateSubCommand1_Cli

dima()aslong,nasintegern=inputbox("请输入n的值：")redima(1ton)callFibonaccia()subFibonacci(a()aslong)dimia

#!/bin/shfun(){sum=0foriin`seq$1$2`dosum=`expr$i+$sum`doneecho$sum}echo"Pleaseinput2number:"readabex

#include#includeusingnamespacestd;intf[1000];//数组记录计算结果intfa(inti){if(i==0)//递归结束条件{f[i]=0;retur

Fibonacci其实就是不断求和,前两个数的和形成第三个数.为方便说明,假设两个变量A和B,A+B=C,C就是和.#!/bin/shfirst=1;echo“$first”#打印第一个数A=1sec

oolflgClick=false;voidOnGUI(){if(GUI.Button(newRect(10,10,50,50),"按钮1")){flgClick=true;}if(flgClick)

[root@localhostbaidu]#morefibonacci.shnum1=0num2=1echo$num1echo$num2couter=$(expr$1-2)#echo$numwhile

#includeusingnamespacestd;intmain(){intf[11]={0,1,1};inti,j,n;for(i=3;i{f[i]=f[i-1]+f[i-2];i

WhiletrueMykey=WaitKey()IfMykey=69ThenKeyPress"a",1KeyPress"s",1KeyPress"c",1EndIfWend

Hwnd=Plugin.Window.Foreground()WhiletrueDelay2000CallPlugin.Bkgnd.KeyPress(Hwnd,65)Wend//WhiletrueWe

输入待测字串: 根据需要自己修改.

懒得开,直接打吧functionout=asdas(a)[m,n]=size(a);temp=1;ifm*n>5fori=1:mforj=1:nout=asdas(i,j)*out;endendels

脚本语言可多了你说的是哪种呢?

假设x为自变量,定义域为[0,10,]补步长为0.1,y为因变量,即函数值,假设函数y=2*x+1；则程序如下；x=0:0.1:10y=2*x+1再问：不是，我的意思是假设是0到10，步长0.1，共1