由键盘输入两个整数,分别计算这两个数的和.差.积.商,并输出结果.

#include"stdio.h"main(){intA,B,C,min;printf("inputA,B,C:");scanf("%d%d%d",&A,&B,&C);min=A;if(min>B){

#include<math.h>main(){ floata,b,c,s,s1;printf("pleaseenter3reals:\n");scanf(&q

voidmain(){intn,i,s;s=1;printf("pleaseinputn:");scanf("%d",&n);for(i=2;i

#includeusingnamespacestd;intmain(){inti,n,s=0;coutn;s=0;for(i=1;i

你写的scanf就提出了要求的输入是“数a”“逗号”“数b”,你既然没有给出逗号,那就一直没有给b赋值,你也没有给b一个初始化的值,那么得出的结果就是一个随机数.可以把逗号去掉,这样两个数字之间用个空

#include"stdio.h"main(){inta,b;printf("请输入两个整数(a,b)：");scanf("%d,%d",&a,&b);printf("和：%d\n",a+b);pri

#includemain(){inta,b;scanf("%d%d",&a,&b);printf("最大数为%d\n",a>b?a:b);}

#includemain(){inta,b;printf("输入整数a,b:");scanf("%d,%d",&a,&b);c=func(a,b);printf("a*a+b*b=%d\n",c);}

intfunc(intx,intn){inty;if(n

#includeintmain()//main{inta,b,sum;//先定义再使用printf("请输入两个整数\n");scanf("%d%d",&a,&b);//逗号sum=a+b;print

importjava.util.Scanner;publicclassTest{publicstaticvoidmain(String[]args){System.out.print("请输入第一个整

#includeintmaxY(intm,intn){inti;for(i=n;i>0;i--)if(m%i==0&&n%i==0)break;return(i);}intminB(intm,intn

ntmain(intargc,char*argv[]){charsound[10][5]={"yi","er","san","si","wu","liu","qi","ba","jiu","shi"}

inta,b,max;scanf("%d",&a);scanf("%d",&b);max=Max(a,b);intMax(inta,intb){returna>b?a:b;}再问：确定吗这个答案？再答

#include"stdio.h"voidmain(){\x05intnum1,num2,temp,a;\x05printf("pleaseinputtwonumbers:\n");\x05scanf

#include/*C语言*/intmaxNum(inta,intb){return(a>b?a:b);}voidmain(){inta,b,max;printf("Entertwonumbers!\

给你个可以加减乘除的!#includevoidmain(){floata,b;charc;printf("\n");scanf("%f%c%f",&a,&c,&b);if(c=='+')

上大的吧,给你代码吧.同是难兄难弟.main(){intn,m,i,a;scanf("%d%d",&n,&m);for(i=1;i

intb[4];intsum=0;b[0]=a/1000;//千位b[1]=a%10;//个位b[2]=(a-b[1])%100;//十位b[3]=(a-b[0]*1000)/100;//百位for(

#include//求a和b最大公约数：intyue(inta,intb){intk=1;intt=a>b?b:a;//a大取b,否则取afor(inti=1;i