由X*2 3y*2=6Y

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由X*2 3y*2=6Y
1、求由方程2y-x=(x-y)ln(x-y)所确定的函数y=y(x)的微分dy

第一题,这是个隐函数,两边对x求导得:2y'-1=(1-y')*ln(x-y)+(x-y)*(1-y')/(x-y)=(1-y')*ln(x-y)+(1-y')所以[3+ln(x-y)]y'=ln(x

由y=sinx怎么转变为y=5/2cos(1/2x+π/6)

y=5/2cos(1/2x+π/6)=5/2sin(π/2+1/2x+π/6)=5/2sin(1/2x+2π/3)方法1:y=sinx----->y=sin(x+2π/3)----->y=sin(1/

6(x-y)-2(x+y)=14 3(x-y)+(x+y)=5

设x-y=mx+y=n则6m-2n=143m+n=5解得m=2n=-1即x-y=2x+y=-1解得x=1/2y=-3/2

x+y/2+x-y/3=6,4(x+y)-3(x-y)=-20

由(1)得3x+3y+2x-2y=365x+y=36(3)由(2)得4x+4y-3x+3y=-20x+7y=-20(4)(3)×7-(4)得34x=272∴x=8把x=8代入(3)得y=-4∴x=8y

由y=x^2+4\x^2+1得x^2=y+4\y+ 1

令x^2=y,代入到原式中即可.

{(x+y)/2+(x-y)/3=6 4(x+y)-3(x-y)=-20

{(x+y)/2+(x-y)/3=63(x+y)+2(x-y)=36(1)4(x+y)-3(x-y)=-20(2)由(1)*3+(2)*2得9(x+y)+6(x-y)+8(x+y)-6(x-y)=36

由方程3x-2y+6=0,可得到用x表示y的式子是?当x=-2时y=?

用x表示y3x-2y+6=0移项3x+6=2yy=3x/2+3当x=-2时代入y=3*-2/2+3=0

y=f(x)由x^2+3y^4+x+2y=1所确定,求dy/dx

x^2+3y^4+x+2y=1两边同时对x求导,得到:2x+3*4*y^3*dy/dx+1+2*dy/dx=0(12y^3+2)dy/dx=-1-2xdy/dx=-(1+2x)/(2+12y^3)

y=sin(2x+π/6)+3/2 怎么由平移 y=sinx 得到

y=sinx先向左平移π/6,得y=sin(x+π/6)然后,纵坐标不变,横坐标变为原来的1/2,得y=sin(2x+π/6)最后,向上平移3/2,得y=sin(2x+π/6)+3/2

设函数y=y(x)由方程y+e^(x+y)=2x确定,求dx/dy

分别对y求导,求左边为1+【e^(x+y)×(dx/dy+1)】右边为2×dx/dy推的dx/dy:自己算下,没得草稿纸.

4(x+y)-3(x-y)=-20,2/x+y+3/x-y=6

第二个方程是不是写错了2/(x+y)+3/(x-y)=6是这样吗

设f(u)可导,函数y=y(x)由x^y+y^x=f(x^2+y^2)所确定,则dy=

两边求微分:d(x^y+y^x)=d(f(x^2+y^2))对x^y可以这么看:先把X看成常数,对Y求微分相当于a^Y,再把Y看成常数对X求微分相当于X^a.那么就好用公式了如下:d(x^y)=X^Y

{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1

3(x+y)-4(x-y)=4(x+y)/2+(x-y)/6=1令a=x+y,b=x-y3a-4b=4(1)a/2+b/6=1则3a+b=6(2)(2)-(1)5b=2b=2/5a=(6-b)/3=2

若(x-y)/(x+y)=3 则(x+2y)/(6x-7y)等于

若(x-y)/(x+y)=3那么x-y=3(x+y)x-y=3x+3y故x=-2y所以(x+2y)/(6x-7y)=(-2y+2y)/(6*(-2y)-7y)=0如果不懂,请Hi我,祝学习愉快!

请问怎么由2x-3y+z=0 ,3x-2y-6z=0 得到x=3z,y=4z

2x-3y+z=0(1)3x-2y-6z=0(2)(1)*2-(2)*34x-6y+2z-9x+6y+18z=0-5x+20z=05x=20zx=4z(1)*3-(2)*26x-9y+3z-6x+4y

由题意:(10Y+X)-(10X+Y)=(100X+Y)-(10Y+X) Y=6X 怎么算的啊 发一些详细的

去括号:10Y+X-10X-Y=100X+Y-10Y-X9Y-9X=99X-9Y移向:18Y=108X解得:Y=6X

函数y=f(x)由方程xy^2+sinx=e^y,求y′

两边对x求导xy^2+sinx=e^yy^2+2xyy'+cosx=e^y*y'y'(e^y-2xy)=y^2+cosxy'=(y^2+cosx)/(e^y-2xy)

隐函数微分法的问题 设由y=2xarctan(y/x)确定y=y(x),求y',y

y=2xarctan(y/x)(y/x)'=(y'/x-y/x^2)(arctanu)'=1/(1+u^2)y'=2arctan(y/x)+2x*(y'/x-y/x^2)*[1/(1+(y/x)^2)