用递归法求fibonacci数列前20项.1,1,2,3,5
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#includeunsignedintFibonacci(intn);intmain(void){inti;for(i=1;i
dimf()asdoublen=inputbox("in","NO.")redimf(n)asdoublef(1)=1f(2)=1fori=3tonf(i)=f(i-1)+f(i-2)nextprin
intfunction(intn){if(n==0)return0;elseif(n==1)return1;elsereturnfunction(n-1)+function(n-2);}
PrivateSubCommand1_Click()n=InputBox("请输入阶数n:")s=f(n)Printn&"!="&sEndSubPrivateFunctionf(ByValnAsInt
把以下程序另存为fib.m%>>fib(8)Fibonacci=123456781123581321
这程序没错,应该是你输入了一个比较大的值,导致递归的层次超过编译器的堆栈的大小,而引发的异常,一般用数组来计算Fibonacci数,用递归局限性太大了,估计100就与越栈了再问:(⊙o⊙)哇,一看就是
#include#includevoidfun(intn){\x09inti;\x09int*a=(int*)malloc(n*sizeof(int));\x09a[0]=a[1]=1;\x09for
//很简单,应该是答案印错了//不过这样才是正确的递归方式doublelegendre(intn,doublex){if(n==0)return1;elseif(n==1)returnx;elsere
#include#defineCOL10//一行输出10个longscan(){//输入求fibonacci函数的第N项intn;printf("InputtheN=");scanf("%d",&n)
大于4000的最小项41815000之内的项数01123581321345589144233377610987159725844181Pressanykeytocontinue
递归算法intfib(intn){//求fibonacci数列第n个数if(n==1||n==2)return1;elsereturnfib(n-1)+fib(n-2);}非递归intfib(intn
#includelongfib(intn){inta;if(n==1)a=1;elseif(n==2)a=1;elsea=fib(n-1)+fib(n-2);returna;}voidmain(){\
#includeintf(inti){if(i==1||i==2)return1;elsereturnf(i-1)+f(i-2);}voidmain(){intn,j;scanf("%d",&n);f
#includeusingnamespacestd;intfibonacci(inta){inttem;intf1=1;intf2=1;while(f2
#includeintgcd(int,int);voidmain(){inta=0,b=0;intmax=0,min=0;scanf("%d%d",&a,&b);max=gcd(a,b);min=a*
longfib(intn) { if(n==0)return0; if(n==1)return1; if(n>1)returnfib(n-1)+fib(n-2); }
publicclassFibonacci1{publicstaticlongfib(intn){longf1=1,f2=1;longm=0;if(n
#includeusingnamespacestd;intmain(){\x09inta[1000001];\x09intn,i;\x09a[1]=a[2]=1;\x09cin>>n;\x09for(
#includeintgys(inta,intb){\x09intr;\x09r=a%b;\x09if(r==0)returnb;\x09elsereturngys(b,r);}voidmain(vo
//fibonacci数列:11235813213455...#includedoublefib_val[100]={0};doublefibonacci_1(intn)//递归,计算时间长,n最好不