用while循环,计算1到1000之间,有多少个能被7整除的数字-搜答案-搜搜考试网

#!/bin/bashsum=0i=2while(($i

us=0;fori=1:10rus=rus+factorial(2i+1);endk=1;rue=0;whilek

////////////////////下面是whileintsum=0;int_i=0;while(_i

intsum=0;for(i=1;i

intn=1;intsum=0do{if(n%3==0)sum+=n;n++;}while(n

publicstaticvoidmain(String[]args)throwsIOException{inti=0;intcount=0;while(i

while语句：#includeinti=0,sum=0;main(){while(i

#includeintmain(){inti=0,sum=0;printf("用while计算机的\n");while(i

varn,s:longint;beginn:=1;s:=1;whiles1000;write(n);end.

好象楼下两个算不出正确值的!doublesum=0;for(inti=1;i

//用whileinti=1,sum=0;while(i

#includeintmain(){inti=101,sum=0;while(i--){sum+=i;}printf("1+2+3+.+100=%d\n",sum);return0;}

上一楼的程序有问题,现改正如下：i=3;j=2;S1(1)=1whileS1(j-1)

#include"stdio.h"#include"math.h"main(){intn=1;floatterm=1.0,sign=1,sum=0;while(n

inti=1;intres=1;while(i

functionans=FOR(n)sum=0;fori=1:nsum=sum+i^i;i=i+1;endans=sum;functionans=WHILE(n)sum=0;i=1;whilei

#include//whileintexp1(inttemp1){inti=1;intterm=1;while(i

java的publicstaticvoidmain(String[]args){intn,i;intPorM;doubles;doublep;s=0;PorM=1;for(n=1;n

//计算1-110的和（while,for,do-while）inti=1;intsum=0;while(i

#includevoidmain(){doublen=1.0,temp=1.0,e=1.0;do{temp=temp/n;e+=temp;n=n+1;}while(temp>=1e-6);printf