用c语言输入一个华氏温度,转换输出摄氏温度.转换公式为:

#include"iostream.h"voidmain(){doubleF,c;coutF;c=(F-32)*5/9;cout

#includeusingnamespacestd;doublecentigrade(doubleF){doubleC=(F-32)*5.0/9;returnC;}intmain(){doubl

因为你定义的变量是float类型,而如果输入5和9的话,电脑会认为是两个整形数据先相除,然后再转换成float型,所以就变成0了.

intmain(){floatc,f;printf("pleaseinputthef=");scanf("%f",&f);c=5/9*(f-32);printf("thec=%f",c);}再问：你运

#includevoidmain(){floatc,f;scanf("%f",&f);c=5.0/9*(e-32);printf("%f",c);}

代码#includevoidmain(){doublea,c;scanf("%lf",&a);c=9.0/5*(a-32);printf("%.2lf\n",c);}

用这个程序可以实现#includefloatchange(floatx);voidmain(){floatfahr;printf("请输入摄氏温度:");scanf("%f",&fahr);print

includeintmain(){floatfahr,celsius;scanf("%f",&fahr);celsius=5.0*(fahr-32)/9;printf("fahr=%.6f",fahr

#includeintmain(){inti,n,m;scanf("%d%d",&n,&m);if(n>m){intt=n;n=m;m=t;}printf("fahrcelsius\n");for(i

第一个问题：可以用个switch语句选择输入华氏还是摄氏,再用相应的转换公式即可；第二个问题：floatf=1,e=1;//forfor(inti=1;i=10^-4){f*=i;e+=1/f;}希望

#includemain(){floatc,h;while(1){printf("PleaseinputtheC:");scanf("%f",&c);if(c!=0){printf("TheHis:%

#includevoidmain(){floatf;scanf("%f",&f);printf("%f",(f-32)*5/9);}

1.#includeintsheshi(floatfw){floatsw;sw=(5.0/9.0)*(fw-32);printf("thecentigradetemperatureis:%f",sw)

#includeintmain(){floatf,c;//f表示华氏温度,c表示摄氏温度printf("请输入华氏温度：\n");scanf("%f",&f);c=f-273.5;//额你给的公式好像

如果是小写,则将这个字符减去32,再输出.反之,加上32就是了.#includemain(){charch;printf("input:");scanf("%c",&ch);if(ch>='a'&&c

#includemain(){floatf,c;printf("pleaseenterF:");scanf("%f",&f);c=5.0*(f-32.0)/9.0printf("%f",c);}

#include<stdio.h>int main(){    float F,c;   &nbs

#includevoidmain(){intc;floatF;printf("C\tF");for(c=0;c

#includeintmain(){floatF,c;while(1){printf("请输入华氏温度：");scanf("%f",&F);c=5*(F-32)/9;printf("摄氏温度为：%0.

华氏温度与摄氏温度的转换,可以运用公式C=5/9(F－32)来求得.如果已知F=4102,那么,转换成摄氏温度是多少呢?其求解步骤为：