f(x)=cos(wx ?)(w>0), ?是f(x)导函数 则w的取值范围

f(x)=sin(π-wx)coswx+cos²wx=sinwxcoswx+cos²wx=(1/2)sin2wx+(1/2)cos2wx+1/2=(√2/2)sin(2wx+π/4

f(x)=sin(wx+阿发)+cos(wx+阿发)=√2[√2∕2sin(wx+阿发)+√2∕2cos(wx+阿发)]（提取√2,根号2）=√2[cos45°sin(wx+阿发)+sin45°cos

1)∵cos(wx+π/3)+cos(wx-π/3)=coswxcosπ/3-sinwxsinπ/3+coswxcosπ/3+sinwxsinπ/3=coswxf(x)=根号3sinwx+cos(wx

（1）f(x)=√3sinwxcoswx-cos²wx+1/2=√3/2sin2wx-1/2cos2wx=sin(2wx-π/6)∵图像两相邻对称轴的距离为π/4∴T/2=π/4∴T=π/2

f(x)=sin(π-wx)coswx+(coswx)^2=sinwxcoswx+(1/2)cos2wx+1/2=(1/2)sin2wx+(1/2)cos2wx+1/2=(√2/2)sin(2wx+π

f(x)=sin(wx+φ)+cos(wx+φ)=√2sin(wx+φ+π/4)T=2π/w=πw=2f(x)=√2sin(2x+φ+π/4)f(-x)=f(x),所以f(-π/8)=f(π/8)si

f(x)=√[(√3)²+1²]*sin(wx+q-z)=2sin(wx+q-z)tanz=1/√3所以z=π/6f(x)=2sin(wx+q-π/6)sin的对称轴是取最值的地方

f(x)=（1/根号2）sin(2w+pi/4)+1+2所以w=1,最小值是1,x=0时

首先f(-x)=f(x),得出是关于Y轴对称,f(0)要不是最大值,要不是最小值,排除B,D因为g的绝对值小于n/2,n就是PAI,所以单从SIN和COS上考虑,SIN移动一个正数（这个正数小于n/2

易得f(x)=sin(wx+q)+cos(wx+q)=√2sin(wx+q+π/4),最小正周期为pai得w=2,f(-x)=f(x)得q=π/4,所以=√2sin(2（x+π/4）),求导后f(x)

∵f（x）=2cos²wx/2+cos（wx+π/3）=coswx+cos（wx+π∕3）+1=cos｛[（wx+wx+π∕3）/2]+[（wx-（wx+π∕3））/2]｝+cos｛[（wx

f(x)=2sin(wx+θ)×cos(wx+θ)+[2cos^2(wx+θ)-1]=sin(2wx+2θ)+cos(2wx+2θ)=√2sin(2wx+2θ+π/4)最小正周期为2π,所以2π/(2

(1)解析：∵函数f(x)=cos(wx+f)(w>0,-π/2<f<0)的最小正周期为π∴w=2π/π=2,f(x)=cos(2x+f)∵f(π/4)=√3/2f(π/4)=cos

A=pai/2w=2/3这个步骤很复杂,在纸上才能写全哟..

f(x)=√2sin(8（x/4+π/2)+φ）因为加了个π/2所以变成了cos所以变成偶函数

w=2,y=(正负)兀/6

(1)f(x)=√3sin(wx+φ)-cos(wx+φ)=2sin(wx+φ-π/6)相邻对称轴间的距离为π/2,最小正周期为π所以w=2π/π=2又知f(0)=2sin(φ-π/6)=00

f(x)=√2sin(wx+φ+π/4)2π/w=πw=2f(x)=√2sin(2x+φ+π/4)f(-x)=√2sin(-2x+φ+π/4)f(x)=f(-x)sin(2x+φ+π/4)=sin(-

f(x)=sin(wx+φ)+cos(wx+φ)=√2sin（x+π/4+φ）而f（x）是偶函数,故f（x）关于x=0对称所以π/4+φ=kπ+π/2（k是整数）而,|φ|