搜搜考试网求y=2Sin(2x 3)导数
来源：学生作业帮助网 编辑：作业帮 时间：2024/04/30 05:58:56
本题考查的是函数的求导原则,总共有三大类：①f(x)±g(x)②f(x)*g(x)③f(x)/g(x)
求函数导数y=e^2x*sin^2xy′=2e^(2x)sin²x+2e^(2x)sinxcosx;很高兴为您解答,skyhunter002为您答疑解惑如果本题有什么不明白可以追问,
y=sin∧2(2x-1)的导数y'=2sin(2x-1)*cos(2x-1)*2=2sin(4x-2)
解析sin²3x'=2sin3xsin3x'=6sin3xcos3x6sin3xcos3x'=18cos²3x-18sin²3x所以二阶导数18（cos²3x-
先对ln求导,得1/sin(1+3x^2)然后对真数,即sin(1+3x^2)求导,是cos(1+3x^2)然后对1+3x^2求导,是6x最后相乘y'=6xcos(1+3x^2)/sin(1+3x^2
∵y=cosx*sin(3x+2)∴y'=(cosx)'*sin(3x+2)+cosx*[sin(3x+2)]'=-sinx*sin(3x+2)+cosx*3cos(3x+2)=3cosxcos(3x
y'=f'(sinx^2)*cosx^2*2x-f'(cosx^2)*sinx^2*2x
再答：满意请采纳谢谢
y=sin²2xy′=2×(cos2x)×2sin2x=4cos2x·sin2x=2sin4xy〃=2(4x)′cos4x=8cos4x
y＝2sin²(2x+π/3)＝1-cos(4x+2π/3).∴y'＝sin(4x+2π/3)·(4x+2π/3)'＝4sin(4x+2π/3).
y‘=[sin²(cos3x)]'=2sin(cos3x)×[sin(cos(3x))]'=2sin(cos3x)cos(cos(3x))(cos3x)'=sin[2(cos3x)]×(-s
2*cos(x^2)*x/sin(x)^2-2*sin(x^2)*cos(x)/sin(x)^3
偏导数x=cos（x^2+y^2+z^）*2x同理想y,z的偏导数只是把cos（）外边的x换成相应的y,z即可
y=1+1/2*sinxy'=1/2*cosx
答：因为：(sinx)'=cosxy=-(sinx)^2y'(x)=-2sinx*(sinx)'y'(x)=-2sinxcosxy'(x)=-sin(2x)