c语言输出1到100能被3和5整除的数,8个数为一行定义n和j
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/15 10:30:39
for(i=1,i
#includemain(){inti;for(i=100;i
intmain(void){inti;intsum=0;for(i=0;i
#includevoidmain(){inti,sum=0;for(i=0;i
#includevoidmain(){intm=0;for(inti=1;i
【1】fac(i);【2】intf;for(;n
#includevoidmain(){inti=1,a=0,b=0;for(i;i
#includevoidmain(){inti;for(i=102;i
//#include"stdafx.h"//vc++6.0加上这一行.#include"stdio.h"voidmain(void){inti,j,k;for(i=15;i
#includeintmain(){for(inti=1;i
#includevoidmain(){inti,j=0;for(i=1;i
还要写吗?再问:不会啊,怎么写呢?再答:你等下,我帮你写一个再答:参考代码:#include#includeintmain(intargc,char*argv[]){\x09inti,j=0;\x09
voidmain(){intsum=0;for(inti=2;i
C语言版本如下:#includeintmain(){inti,sum=0;for(i=1;i
哈哈,太简单了soeasy代码如下,测试通过!:#includeintmain(void){inti,count=0;for(i=1;i
intsum=0;for(inti=9;i
/楼主还是多多看看课本、#include <stdio.h>int main(){int sum = 0;int i;fo
能被这三个同时整除还是?只要满足一个就行?再问:同时的啊、谢谢再答:aver=1963Pressanykeytocontinue#include"stdio.h"main(){inti,sum=0,c
intn;scanf("%d",&n);if(n%5==0&&n%7==0){printf("YES");}else{printf("NO");}
#includeintmain(){inti,n,sum;doubleaver;n=0;sum=0;for(i=100;i