c语言编程输出100-200之间能被3整除的整数,并统计其个数.-搜答案-搜搜考试网

#includevoidmain(){inti;for(i=1;i再问：亲，我们选修课是c语言，我一点点不懂。这个是老师出的编程题，是最后的考试题。也要这样写到卷纸上么？再答：这个程序没有问题。只是在

#includemain(){inti;for(i=100;i

#include <stdio.h>int diffabs(int a,int b) { // 返回a,b差值的绝对值

#include#defineN4main(){inti,j,a[N][N]={{3,5,6,3},{0,8,9,1},{0,0,5,0},{0,0,0,7}};for(i=0;ifor(j=0;ji

#includevoidmain(){intx,a,b,c;scanf("%d",&x);a=x/100;b=x/10%10;c=x%10;x=c*100+b*10+a;printf("%d",x);

#include<stdio.h>int main(){int i,j;for(i=0;i<6;i++){for(j=1;j<6-i;j++)

#include"stdio.h"voidmain(){inti,j,n,k=0;scanf("%d",&n);for(i=0;i

longfunc(intm){inti,sum=1;for(i=1;i

//#include"stdafx.h"//vc++6.0加上这一行.#include"stdio.h"voidmain(void){inti,j,k;for(i=15;i

哈哈,太简单了soeasy代码如下,测试通过!：#includeintmain(void){inti,count=0;for(i=1;i

#includeintmain(){inta,b,c;intmin,max;scanf("%d%d%d",&a,&b,&c);if(amax)max=c;printf("%d%d%d",max,a+b

C语言#includevoidmain(){inti;for(i=1;i

#include"stdio.h"voidmain(){inti;for(i=200;i

直角三角形#include#defineN10intmain(){inti,j;for(i=1;i再问：if(j

#includevoidmain(){intk,sum=0;for(k=1;k

#includeintmain(){inti;intsum=0;for(i=1;i{if(0!=i%7){sum+=i;}}printf("sum=%d\n",sum);return0;}

#defineN5#include<stdio.h>voidmain(){ inta[N][N]; inti,j; for

第一个#includemain(){printf("****\n");printf("***\n");printf("**\n");printf("*\n");}第二个#includemain(){p

#includevoidmain(){inti=1,count=0;for(;i

voidmain()intx,abs;printf("shurux");scanf("%d",&x);if(x>0)abs=x;elseabs=0-x;printf("jueduizhishi%d",