c语言编程实现将最小值与第一个数交换,输出交换后的n个数

#include <stdio.h>int ok(int n){  int i = n %&nbs

给你个参考

#include"stdio.h"intmain(){inti,index,n;inta[100];printf("Entern:");scanf("%d",&n);printf("Ente

#include<stdio.h>voidinput(intb[10]){inti;for(i=0;i<10;i++)scanf("%d",&b[i]);

题目2：#includevoidmain(){inta,b;printf("将237转换成小时和分钟输出\n");a=237/60;b=237%60;printf("hour:%d\nmin

#includevoidmain(){inta,b,c,max,min;printf("请分别输入a,b,c三个数:\n");scanf("%d%d%d",&a,&b,&c);max=min=a;if

#includevoidmain(){inta[10],min,max,i,k;for(i=0;i

#include//函数,读数操作数intgetNextNum(){intret;scanf("%d",&ret);returnret;}//函数,读运算符chargetOpt(){returnget

#include<string.h>void main(){\x09char s[10],i,j,t,k;\x09printf("输入一个整数(不大于十位):

#include#includevoidmain(){intn,a,b,bTemp;int*p;printf("howmanynumbers?\n");scanf("%d",&n);p=malloc(

#includeintmax(intn);voidmain(){inta,b;printf("Pleaseinputnumber,endof-1:");scanf("%d",&a);while(a!=

我来#include#include"stdlib.h"#include"time.h"main(){inti,j,*p,arry[3][4];p=arry[0];srand((unsigned

#includeintmain(){inti,max,min,n,a[105];scanf("%d",&n);scanf("%d",&a[1]);max=a[1];min=a[1];for(i

#include <stdio.h>#include <stdlib.h>int main(){  int i,&n

#includeintmain(){\x09inti,sum=0;\x09for(i=1;i

#include <stdio.h>#include <stdlib.h>int main(){  char *a[

#includeintmain(void){intmax,min;inta,i;printf("Input10interger:");scanf("%d",&a);max=min=a;for(i=0;

#include"stdio.h"main(){intinteger,i,max,min,sum;max=0;min=100;sum=0;for(i=1;i100||integermax)max=in

#include"stdio.h"voidmain(){voidzhuan(intarray[2][3],intb[3][2]);intarray[2][3],b[3][2];inti,j;print

你的有两个明显的错误1scanf("%d",a[i]);输入数据应该取地址&a[i]2for(j=0;ja[j])j=0时a[j-1]的下表就是a[-1]这绝对是个大错.再问：#includeintm