数学多项式乘多项式的计算题
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第一题(a+2b+2c)×(a+2b-2c)=[(a+2b)+2c]×[(a+2b)-2c]=(a+2b)^2-4c^2=a^2+4ab+4b^2-4c^2第二题(a-b)×(a+b)×(a²
按照乘法分配律临摹.2a²b(½ab-3ab²)=a³b²-6a³b³(x/3-xy/4)x(-12y)=-4xy+3xy
1)0.2×3.1+0.2+6.7×0.2=2)1.7×1.8+18×1.7=3)45.5×2.3-0.23-2.3×15.7=4)69.5×3.3-0.33-3.3×29.8=5)19.3×0.3-
计算(xy-x^2)/((x-y)/xy)急用简单讲一下过程,-x^2y(xy-x^2)/((x-y)/xy)=-x(x-y)*xy/(x-y)=-x^2y
亲!写纸上给你可以吗?再答:
①(2x-3)(x-4)-2(x-1)(2+3x)-(2x-5)(x+3)=31-10x-6x^2②(3x-2)(2x+3)-6x(x-1)≤2(x-2)9x再问:能把过程写的详细点吗?拜托啦~再答:
1(2a+b)(a-2b)2(a+b)^23(x^2+xy+y^2)(x^2-xy+y^2)4(2x^4-3x^3+5x^2+x)(-x+1)5(x+1)(x+2)(x+3)6(2x+3y)(3x-2
(1)(2a+1)(-a-1)(2)(-2a+1)(-2a+1)(3)(x+2y)(x2-2xy+4y2)4、(3x2+2x-5)(x-2)5、-2x·(3x2-4x-1)-2x(3x2-1)6、(-
-x^2y(xy-x^2)/((x-y)/xy)=-x(x-y)*xy/(x-y)=-x^2y
表达很混乱,次方用^号表示,多用括号以减少表达式歧义.再说,这种题又不难.自己动手,丰衣足食!
(a+b+c)×(d+e+f)=ad+ae+af+bd+be+bf+cd+ce+cf(a+b)×(a-b)=a^2-b^2(a+b)×(a+b)=(a+b)^2=a^2+2ab+b^2(a+b+c)×
1(2a+b)(a-2b)2(a+b)^23(x^2+xy+y^2)(x^2-xy+y^2)4(2x^4-3x^3+5x^2+x)(-x+1)5(x+1)(x+2)(x+3)6(2x+3y)(3x-2
n(n+5)-(n-3)(n+2)=n^2+5n-n^2-2n+3n+6=6n+6=6(n+1).显然对任意自然数n,6(n+1)都能被6整除.
用待定系数法(X^2+2X+3)(ax+b)=ax^3+(b+2a)x^2+(3a+2b)x+3b所以(3a+2b)=0b+2a=1解得a=2b=-3
B③a+b-2b-a=-b④acx²+axd+bcx+bdCBD10X-10-29
具体的题目呢?
3(-4x+y)(x-y)+2(3x-2y)(x+3y)x=-2y=1=(-12x+3y)(x-y)+(6x-4y)(x+3y)=-12x²+12xy+3xy-3y²+6x&sup
1、(a+b)(a²-ab+b²)=(a+b)(a²-2ab+b²+ab)=(a+b)[(a-b²)+ab]2、a³(a²-2)-
1).(-a)^2·(-a)^3=(-a)^(2+3)=(-a)^5=-a^5(-x)·x^2·(-x^4)=x*x^2*x^4=x^(1+2+4)=x^7(xy^2)^2=x^2y^42).(-2*