c==输入一个浮点数,输出这个浮点数的绝对值

#include#includevoidmain(){doublex,y;printf("请输入x和y坐标,用空格隔开\n");scanf("%lf%lf",&x,&y);doublel=sqrt(x

intmain(intargc,char*argv[]){intinput;intret,num;printf("Inputaint:");scanf("%d",&input);for(;;){num

#includevoidmain(){intx,a,b,c;scanf("%d",&x);a=x/100;b=x/10%10;c=x%10;x=c*100+b*10+a;printf("%d",x);

#includeusingnamespacestd;intmain(void){floatf;scanf("%f",&f);printf("整数部分:%d\n",int(f));printf("小数部

可以把浮点数当初字符串来处理字符串处理函数如下：voidcut(string&str){intn=0;n=str.size()-1;stringcutter(n,'');stringstr3(n,''

printf("%.3f",变量)；试试看,貌似是这样……

程序没有错,可能是你输入的格式错了数与数之间用英文状态下的逗号隔开,

importjava.util.Scanner;publicclassTest{publicstaticvoidmain(String[]args){Scannerinput=newScanner(S

scanf("%d,%d,%d,&a,&b,&c");改成scanf("%d,%d,%d“,&a,&b,&c);printf("thelargerstnumberis%d\n,max");改成prin

#include#includeusingnamespacestd;doublemin(double*x,double*y);intmain(){doublea,b;cin>>a;cin>>b;if(

方法一：你可以先将浮点数乘以100,然后取整,非四舍五入,取整后再除以100,这样不就得到了两位小数的输出了嘛方法二：你还可以强制转换为String的,然后取从开始到小数点往后两位的位置结束的字符串,

usingSystem;usingSystem.Collections.Generic;usingSystem.Linq;usingSystem.Text;namespacetest{classPro

#includedoublemin(doublea,doubleb){reurn((a>b)b:a);}intmain(){doublea,b,c;printf("输入三个浮点数(用逗号","隔开):

int main(){double a=5.2,b=3.1;printf("%lf %lf %lf %lf\n",a+b,a-b,

c语言本省就有求浮点数绝对值的函数:fabs

#includeintmain(){inti,a;printf("Enternumber:");scanf("%d",&a);for(i=0;i

#includedoublef(floatx){if(x

#includemain(){intn,sum=0;scanf("%d",&n);for(inti=0;i

#include#includeintmain(){chars[10]="ABCDE";printf("请输入一个字符和一个数字,以逗号分隔:");inta;charb;scanf("%c,%d",&

把结果加上0.005再截断.#include"stdio.h"intmain(){floata=1.2365f;floatb=(float)(int)((a+0.005f)*100)/100;prin